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ycow [4]
4 years ago
8

TexFormula1" title=" \frac{5x + 50}{x + 5} . \frac{1}{x + 10} " alt=" \frac{5x + 50}{x + 5} . \frac{1}{x + 10} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
bezimeni [28]4 years ago
8 0
Hi, I'd be glad to help you with this equation. 

Your answer is (5/ x + 3) 

Hope this helps. 
Have a great day!
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28b

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Assuming x > 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s
ehidna [41]
The answer is <span>104 x times the square root of 5 x 
</span>
<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span>11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245}  *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\  \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\  \\ =11* \sqrt{5}  * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\  \\ &#10;=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\  \\ &#10;=77x* \sqrt{5*x} +27x* \sqrt{5*x}  = \\  \\ &#10;=77x \sqrt{5x} +27x \sqrt{5x} = \\  \\ &#10;=104x \sqrt{5x}
4 0
3 years ago
Read 2 more answers
Answer Is not C<br>please help​
Katyanochek1 [597]

Answer:

B

Step-by-step explanation:

Well since it is arthimetic sequence we know the formula

We know d is difference between second term and first so it will be -5- (-12)= -5+12= 7

a_{n}= a _{1}+ d (n-1) \\a_{n}= -12+7(n-1)\\a_{n} = -12+7n-7\\a_{n}= 7n-19

the domain of this is 1,2,3,4.......

range is -12,-5,2,9.......

Therefore answer is B.

5 0
3 years ago
Please help 50 pts and brainliest if correct
kap26 [50]

Answer:

C

Step-by-step explanation:

it makes sense yah?

5 0
3 years ago
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