Question

Arithmetic sequence a1=8 d=9

Answer 1

Answer:

$\ \ \ \ \ \ a_n=8+9(n-1)\\\implies a_n=8+9n-9\\\implies a_n=9n-1$

Step-by-step explanation:

arithmetic sequence equation:

$a_n=a+(n-1)d$

where a is the first term and d is the common difference

Therefore,

$\ \ \ \ \ \ a_n=8+9(n-1)\\\implies a_n=8+9n-9\\\implies a_n=9n-1$