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oksian1 [2.3K]
4 years ago
13

HELP! What is the solution of the equation when solved over the complex numbers?

Mathematics
2 answers:
lubasha [3.4K]4 years ago
7 0

Answer:

±2i\sqrt{6} = x

Step-by-step explanation:

0 = {x}^{2} + 24 \\ \\ -24 = {x}^{2} \\ \\ \sqrt{[4][6][i]} = \sqrt{{x}^{2}} \\ \\ ±2i\sqrt{6} = x

The square root of something is ALWAYS negative and positive.

I am joyous to assist you anytime.

alisha [4.7K]4 years ago
4 0

Answer:

not possible

Step-by-step explanation:

x^2+24=0

x^=-24

not possible as a sguared # can't be neg.

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Answer:

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kotykmax [81]
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3 years ago
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3 years ago
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