A.
2/3A=-24
time both sides by 3/2
A=-72/2
A=-36
B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
-4=B
distance between 2 points x and y is |x-y|
so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
Answer:
112
Step-by-step explanation:
Just solve it easy peasy
![7[(25+9)-3(2-1)]](https://tex.z-dn.net/?f=7%5B%2825%2B9%29-3%282-1%29%5D)
First solve the inner brackets
![7[(34)-3(3)]\\7[25-9]](https://tex.z-dn.net/?f=7%5B%2834%29-3%283%29%5D%5C%5C7%5B25-9%5D)
Now the other brackets
![7[25-9]\\7[16]\\112](https://tex.z-dn.net/?f=7%5B25-9%5D%5C%5C7%5B16%5D%5C%5C112)
For the first digit there are 7 choices. For the second digit there are 6 choices (because we can't use the same one again). And so on, until there is only one choice for the last digit.
The number of possible codes is this:
7*6*5*4*3*2*1 = 7! = 5040
Answer:
v= 3
Step-by-step explanation:
-19 + v = -8 ( v - 1 )
multiply -8(v - 1)= -8v + 8
-8v + 8v and then add the v with the +8v
Subtract -19 +19 and add the +19 with the +8= 27
27 divided by 9= 3
Answer:
w = 7m
l =9 m
Step-by-step explanation:
Let w = width
l = w+2
A = l*w
63 = (w+2) * w
63 = w^2 +2w
Subtract 63 from each side
0 = w^2 +2w - 63
Factor
What 2 numbers multiply to -63 and add to 2
9*-7 = -63
9-7 = 2
0 = (w +9) ( w-7)
Using the zero product property
w+9 =0 w-7 =0
w = -9 w = 7
Since we cannot have a negative length
w=7
l =w+2 =7+2 = 9
