14a^2bc^4/21abc^6 = 2a/3b^2
Answer:
Given:
I usually walk from home to work. This morning, I walked for 10 minutes until I was halfway to work.
I then realized that I would be late if I kept walking.
I ran the rest of the way. I run twice as fast as I walk.
Find:
The number of minutes in total did it take me to get from home to work
Step-by-step explanation:
Had I kept walking, the second half of my trip would have taken 10 more minutes.
By doubling my speed for the second half of my trip,
I halved the amount of time it took me to finish.
So, the second half of my trip took 5 minutes, for a total trip time of 10+5 = 15 minutes.
The number of minutes in total did it take me to get from home to work is 15 minutes.
On Friday, Beth will most likely do 39 sit ups. Every day she is doing an extra 6 sit ups.... Thursday would be 33 sit ups and Friday would be 39 sit ups.
Answer: r = 11
Step-by-step explanation:
We know that the point (-2, r) lies on the graph of:
2*x + y = 7.
Then, if we that point is on the graph of the equation, we can replace the values and we will have:
2*(-2) + r = 7
and now we solve this for r-
-4 + r = 7
r = 7 + 4 = 11
r = 11
Answer:
95 mi/hr
Step-by-step explanation:
475/5 = 95
285/3 = 95