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Lorico [155]
3 years ago
11

a box was measured with a degree of accuracy to the nearest 2cm; 24cm x 24cm x 20cm. what is the largest possible volume of the

box to the nearest cm3
Mathematics
1 answer:
DochEvi [55]3 years ago
5 0
For any value, e.g. a, to the nearest x units, the upper and lower bounds are:
(a + x/2) and (a - x/2)
For your question, there are three dimensions so:
Dealing with the first one, we have 24 cm to the nearest 2 cm so the boundaries are:
Upper boundary: 24 + 2/2 = 25
Lower boundary: 24 - 2/2 = 23
The second dimension is the same as the first in value and is also given to the nearest 2 cm so the boundaries are the same as for the first.
The third dimension is 20 cm to the nearest 2 cm so the boundaries are:
Upper boundary: 20 + 2/2 = 21
Lower boundary: 20 - 2/2 = 19

To get the largest possible area, we take the upper bounds of all the dimensions and multiply them so:
25 * 25 * 21 = 13125 cm³
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nika2105 [10]
Let's call the distance from the beach to the playground x.
Let's call the distance from the stand to the parking lot z.
Let's call the base of the biggest triangle in the picture (from the parking lot to the left) y.

Recall the pythagorean theorem: the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse.

There are three right triangles we can work with.

Triangle with sides 48, x and z. Here z is the hypotenuse so we get the equation x^{2} + 48^{2} = z^{2}

Triangle with sides 27, x and y. Here y is the hypotenuse so we get 27^{2} + x^{2} = y^{2}

Triangle with sides z, y and (48+27). Here (48+27) is the hypotenuse so we get y^{2} + z^{2} = (27+48)^{2}. That is, y^{2} + z^{2} = 5625

We have 3 equations and 3 unknowns (x, y and z). So let's take the last equation: y^{2} + z^{2} = 5625 and replace z^{2} and y^{2} using expressions that contain an expression in terms of x from the first two equations we came up with.

That gives us: 48^{2} + x^{2} + x^{2} + 27^{2} =5625 which we solve for x as follows:

2 x^{2} + 3033 =5625
2x^{2}  =2592
 x^{2} =1296
x=36

Now that we know x we can substitute 36 for x into the equation 48^{2} + x^{2} = z^{2} and solve for z as follows:
48^{2} + 36^{2} = z^{2} 
2304+1296=z^{2} 
3600=z^{2} 
z=60

This means that the distance from the beach to the parking lot is 36 m and the distance from the stand to the parking lot is 60 m.
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Step-by-step explanation:


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