For any value, e.g. a, to the nearest x units, the upper and lower bounds are: (a + x/2) and (a - x/2) For your question, there are three dimensions so: Dealing with the first one, we have 24 cm to the nearest 2 cm so the boundaries are: Upper boundary: 24 + 2/2 = 25 Lower boundary: 24 - 2/2 = 23 The second dimension is the same as the first in value and is also given to the nearest 2 cm so the boundaries are the same as for the first. The third dimension is 20 cm to the nearest 2 cm so the boundaries are: Upper boundary: 20 + 2/2 = 21 Lower boundary: 20 - 2/2 = 19
To get the largest possible area, we take the upper bounds of all the dimensions and multiply them so: 25 * 25 * 21 = 13125 cm³
I think if you take 360 and divide it by 55 thats how many busses they used. Then take that answer and divide it by 13 to find how many vans were used.
