The volume of the fish tank is 408 in³
To solve the volume of the fish tank, we need to understand what is the volume of plane shapes.
<h3>What is the volume of plane shapes?</h3>
The volume of plane shapes resembles a 3-dimensional space showing the area enclosed by the shape.
From the figure given:
The figure can be differentiated into two shapes;
The volume of the rectangle is known as:
- = Length × Breadth
- = 7 inches × 6 inches
- = 42 inches²
The volume of the triangle is:
- = 1/2 × base × height
- = 1/2 × 3 × 6
- = 9 inches²
The total volume of the base of the fish tank now is:
- = 42 inches² + 9 inches²
- = 51 inches²
Now, the volume of the fish tank is:
- = Height × base of the fish tank
- = 8 inches × 51 inches²
- = 408 in³
Learn more about the volume of plane shapes here:
brainly.com/question/20475473
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer:
A
Step-by-step explanation:
The other situations do not represent a 60% probability.
B is a situation in which 40% of people prefer aisle seats.
C is a situation in which 33% of people prefer aisle seats
D is a situation in which 66% of people prefer aisle seats.
