The full range is

(length

), so the half range is

. The half range sine series would then be given by

where

Essentially, this is the same as finding the Fourier series for the function

Integrating by parts yields

So the half range sine series for this function is simply
Answer:
<h2>
7</h2>
Step-by-step explanation:
Plugged it in the calc!
Hope it helps :)
<h3>let a number = a</h3><h3>it's cube will be a×a×a = a³</h3>
<h3>now atq 2a </h3><h3>it's cube will be </h3><h3>2a ×2a ×2a => 8a³ or (2a)³</h3>
<h2>Hope it helps you </h2>
Complete the square
isolate x terms
y=(x^2-14x)+53
take 1/2 of -14 and square it ((-7)^2=49
add plus and minus of that inside the parntehasees
y=(x^2-14x+49-49)+53
factor perfect suqrae
y=((x-7)^2-49)+53
get rid of parnthasees
y=(x-7)^2-49+53
y=(x-7)^2+4
C isi answer