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oksano4ka [1.4K]
3 years ago
7

How do you make this equation 13+5y=6x into slope-intercept form?

Mathematics
1 answer:
Reil [10]3 years ago
5 0
In slope-intercept form, the y variable is isolated.
so,
<span>13+5y=6x
Subtract 13 on both sides.
5y=6x-13
Divide by 5 on both sides.
y=6/5 x -13/5</span>
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Oakland Middle school has 128 6th graders, 121 7th graders and 135 8th graders. If there are 3 teachers per 32 students, how man
zepelin [54]

Answer:

36 Teachers in Total

Step-by-step explanation:

I would use Ratio.

Students: 128 + 121 + 135 = 384 total students

Teachers: Students

3 : 32

36 : 384

384 ÷ 32 = 12

12 x 3 = 36

6 0
3 years ago
X - (-3) is the same as x (-3). true false
liq [111]
False

x-1(-3)=x+(-3)
x+3=x-3
3=-3
false

NO
7 0
3 years ago
Read 2 more answers
Y=-3x^2-6x+24
Lera25 [3.4K]
The x-intercept is the point at which the function intersects the x-axis.
For any point on the x-axis, y = 0. Thus we can plug in 0 for y and solve for x.

y=-3x^2-6x+24 \\ 0=-3x^2-6x+24

Let's split the middle on this quadratic.
To do this we need to find two numbers that add to equal -6 and multiply to equal -72. (-3 times 24)
Consider ways to multiply to get 72.
72 = 36 ×2...that's not going to work.
72 = 24 × 3
72 = 18 × 4
72 = 12 × 6...and 12 minus 6 is 6!
Let's add our signs; our numbers are -12 and 6.
Now, split the middle and factor.

0=-3x^2-12x+6x+24\\0=-3x(x+4)+6(x+4)\\0=(-3x+6)(x+4)

Now you should know that anything multiplied by zero is zero.
So any value that makes one of those factors equal zero is an x-intercept.
Solve each of these equations.

-3x+6 = 0
-3x = -6
x = 2

x+4 = 0
x = -4

Oh, and since all parabolas (graphs of quadratics) are symmetrical, our axis of symmetry will be the average between the two, which is x=-1.

Now for our y-intercepts. For any points on the y-axis, x=0, so if we plug in 0 for x and solve for y we'll get our y-intercept.

y = -3×0² - 6×0 + 24
y = 0 - 0 + 24
y = 24

What about our vertex? Well, we know it's going to line up with the axis of symmetry, so let's just plug in -1 for x.

y = -3×-1² - 6×-1 + 24
y = -3×1 -6×-1 + 24
y = -3 + 6 + 24
y = 27

Thus the vertex is (-1, 27)

The y value is not going to exceed 27, as this is a decreasing quadratic, (we already know y=24 is a possibilty) and this equation goes downwards infinitely, so our range is (-∞, 27)

As for x, well, it's sort of the input for our equation, meaning it can be whatever we want it to be. Thus the domain is (-∞, ∞)




3 0
3 years ago
What is the slope of the line passing through the points (-1,-7) and (-9, -2) ?​
Dominik [7]
The equation for slope is:
(y2 - y1) / (x2 - x1)

-2 -(-7) = 5
-9 -(-1) = -8

Slope of the line:

5/-8 or -5/8
7 0
3 years ago
Read 2 more answers
What is vertex of x^2+5x-3
Art [367]

\text{The vertex of}\ ax^2+bx+c:\\\\(h,\ k),\ \text{where}\ h=\dfrac{-b}{2a};\ k=f(h)=\dfrac{-(-b^2-4ac)}{4a}

\text{We have:}\\f(x)=x^2+5x-3\\\\a=1,\ b=5,\ c=-3\\\\h=\dfrac{-5}{2\cdot1}=\dfrac{-5}{2}=-2.5\\\\k=f(-2.5)=(-2.5)^2+5(-2.5)-3=6.25-12.5-3=-9.25

\text{Answer: the vertex is in}\ (-2.5;\ -9.25)

6 0
3 years ago
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