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3 years ago

How do you make this equation 13+5y=6x into slope-intercept form?

1 answer:

5 0

In slope-intercept form, the y variable is isolated.
so,
<span>13+5y=6x
Subtract 13 on both sides.
5y=6x-13
Divide by 5 on both sides.
y=6/5 x -13/5</span>

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The sum of two numbers is 150 the ratio of the same number is 3:2 find the bigger number

Paladinen [302]

$3x-\ bigger\ number\\
2x-\ smaller\ number\\\\
3x+2x=150\\\\
5x=150\ \ \ | divide\ by\ 5\\\\
x=30\\\\
3x=3*30=90\\\\ Bigger\ number\ is\ 90.$

5 0

3 years ago

What is the sum of a 7-term geometric series if the first term is -6, the last term is -24,576, and the common ratio is 4?

Zanzabum

<h3><u>Answer:</u></h3>

Hence, the sum of a 7-term geometric series is:

-32766.

<h3><u>Step-by-step explanation:</u></h3>

We have to find the sum of a 7-term geometric series (i.e. n=7) if the first term(a) is -6, the last term is -24,576, and the common ratio(r) is 4.

We know that the sum of the 7-term geometric series is given as:

$S_n=a\times (\dfrac{r^n-1}{r-1})$

On putting the value of a,n and r in the given formula we have:

$S_7=(-6)\times (\dfrac{4^7-1}{4-1})\\\\\\S_7=-32766$

Hence, the sum of a 7-term geometric series is:

-32766.

3 0

3 years ago

Read 2 more answers

Find the slope of the line that passes through (4, 6) and (1, 10).

Jlenok [28]

Answer:

given us,

(x1y1) = (4,6)

(x2y2)= (1,10)

here

slope= (y2-y1)/ (x2-x1)

= (10-6)/ (1-4)

= 4/ (-3)

Step-by-step explanation:

4/ (-3)

5 0

3 years ago

In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist

Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

$np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96$

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

$\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408$

#Define Y:

Y~(11.04,5.7408)

$P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291$

Hence, the probability of 12 or fewer is 0.8291

b. The probability that 5 or more fish were caught.

#Using normal approximation:

$P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968$

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above $P(X\geq 5)=0.9968$ and a , $P(X\leq 12)$ =0.7291

$P(5\leq X\leq 120\approx P(4.5\leq Y\leq 12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259$

Hence, the probability of between 5 and 12 is 0.7259

4 0

3 years ago

What is the inverse of f(x)=x^-9

Leona [35]

$y = \frac{1}{x^9}\\yx^9 = 1\\x^9 = \frac{1}{y}\\x = \sqrt[9]{\frac{1}{y}}\\Therefore, \ f^{-1}(x)=\sqrt[9]{\frac{1}{x}}.$

3 0

3 years ago