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3 years ago

PLEASE HELPP 6TH GRADE MATH!!

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

Answer: 1- 2:3

2- 4:7

3- draw 5 of something, then one of something else

4- same as 3

5- 10, 3, and 20

6- 14, 21, and 4

Step-by-step explanation:

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1. Write a rule that will take the triangle to a congruent triangle. Write your rule as (x,y)

olga nikolaevna [1]

Transforming a shape involves changing the size and/or the location of the shape.

The rule that will take the triangle to a congruent triangle is $(x,y) \to (x,-y)$
The rule that will take the triangle to a figure that is similar is $(x,y) \to (0.5x,0.5y)$ .
The rule that will take the triangle to a figure that is not similar or congruent is $(x,y) \to (0.5x,2y)$ .

<h3>Rigid transformation</h3>

When a shape is transformed by a rigid transformation, then the image of the shape will be congruent to the original shape.

An example of a rigid transformation is a reflection over the x-axis; and the rule is:

$(x,y) \to (x,-y)$

So, a rule that will take the triangle to a congruent triangle is $(x,y) \to (x,-y)$

<h3>Nonrigid transformation</h3>

When a shape is transformed by a nonrigid transformation, then the image of the shape will not be congruent to the original shape, however the original shape and the transformed shape would be similar

An example of a nonrigid transformation is a dilation by a scale factor od 0.5; and the rule is:

$(x,y) \to (0.5x,0.5y)$

So, a rule that will take the triangle to a figure that is similar is $(x,y) \to (0.5x,0.5y)$

However, if the x and y coordinates of the shape are dilated by different scale factors, then the resulting shape would neither be similar nor be congruent to the original shape.

A rule that will take the triangle to a figure that is not similar or congruent is $(x,y) \to (0.5x,2y)$ .

Read more about transformation at:

brainly.com/question/4289712

6 0

2 years ago

Somebody please help this is due in a couple of hours :(

Luba_88 [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

The population of Townville in 1860 was 1500 people. The population grew at about a rate of 2.8% per year until 1960. What was t

antoniya [11.8K]

It reachs 5800 population in 1960 if i am not wrong. i'll check this out tomorrow right now i do not have enough time for it.

3 0

3 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago

2. If 8.67 is rounded to tenth, 8.67 becomes<br>A. 8.00<br>B. 8.7<br>C. 8.60<br>D. 86.0<br>2.64

andrey2020 [161]

Answer:

b. 8.7

Step-by-step explanation:

7 rounds up turning the 6 besides it into a 7.

4 0

3 years ago

Read 2 more answers