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morpeh [17]
3 years ago
14

PLEASE HELPP 6TH GRADE MATH!!

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer: 1- 2:3

2- 4:7

3- draw 5 of something, then one of something else

4- same as 3

5- 10, 3, and 20

6- 14, 21, and 4

Step-by-step explanation:

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A^3=343 in^3
take the cubic root
a=7
Perimeter= 7in+7in+7in+7in=28inch
4 0
3 years ago
If diameter of a circle is twice as large as the diameter of a smaller circle, What
Leona [35]

The area of a circle uses the radius of a circle, which is 1/2 the diameter.

In the calculation the radius is squared.

Since the diameter of the larger circle is twice as large the radius would be 2 times.

2 squared would be: 2^2 = 4

This means the area of the larger circle is 4 times larger which would make the ratio 4:1

3 0
3 years ago
Jen earns $35,650 a year working for an electronics supplier. She is single with no
Kobotan [32]

Answer: 5% approximately

Step-by-step explanation:

Jen earns $35,650 a year working for an electronics supplier and pays $1,749.80 in state income tax each year. To calculate the income tax rate, we divide the amount paid as tax by her annual income and then multiply by 100. This will be:

= 1749.80/35650 × 100

= 4.91%

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The state's tax rate is 5%.

7 0
3 years ago
Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
4 years ago
Your neighbor needs to put a fence around her front yard and a seperate fence around her backyard. Her front yard is 65 feet lon
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Front yard
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Back yard
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380 feet
5 0
3 years ago
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