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3 years ago

NEED ANSWERED ASAP please find the volume of the cone and cylinder.

Mathematics

2 answers:

Vika [28.1K]3 years ago

5 0

Answer:

volume of cone is 285

volume of cylinder is 95

Step-by-step explanation:

Mkey [24]3 years ago

4 0

Cone volume= 285 ( the radius would be 5.5)
Cylinder volume =95 same radius as well

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What percent of the values are between 10 and 30? Round to the nearest tenth of a percent if necessary.

skad [1K]

Answer: 33.3%

Step-by-step explanation: I did this on saavas. also for part b the answer is 32.5.

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3 years ago

Find the limit of the function by using direct substitution. limit as x approaches four of quantity x squared plus three x minus

Yuliya22 [10]

$\lim_{x \to 4} f(x)=x^2+3x-1$
just subsitute
f(4)=4²+3(4)-1
f(4)=16+12-1
f(4)=28-1
f(4)=27

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3 years ago

Read 2 more answers

Help me and fast please

iogann1982 [59]

Answer: the answer is C

Step-by-step explanation: we know this because a straight line is 180 degrees. So given 140 degrees we know that g= 40.

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3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

I need the reasoning?

morpeh [17]

Answer:

2. This is only true when x=-3.

3. This is only true when x=3.

4. This is only true when x=12.

5. This has no solution.

6. This has an infinite number of solutions.

6 0

3 years ago

NEED ANSWERED ASAP please find the volume of the cone and cylinder. ​

NEED ANSWERED ASAP please find the volume of the cone and cylinder.