Answer:
y = -2x^2(x - 3)
Step-by-step explanation:
<em><u>Preliminary Remark</u></em>
If a cubic is tangent to the x axis at 0,0
Then the equation must be related to y = a*x^2(x - h)
<em><u>(3,0)</u></em>
If the cubic goes through the point (3,0), then the equation will become
0 = a*3^2(3 - h)
0 = 9a (3 - h)
0 = 27a - 9ah
from which h = 3
<em><u>From the second point, we get</u></em>
4 = ax^2(x - 3)
4 = a(1)^2(1 - 3)
4 = a(-2)
a = 4 / - 2
a = -2
<em><u>Answer</u></em>
y = -2x^2(x - 3)
Answer:
11
Step-by-step explanation:
AB = 3x + 4 and AC which is twice of AB is equal to 11x - 17
2 (3x + 4) = 11x - 17
6x + 8 = 11x - 17
8 + 17 = 11x - 6x
25 = 5x
5 = x
AC = CD = 11x - 17 ➡ 11×5 - 17 = 38
CD = 38 and DE = 49 - 38 = 11
Answer:
Pretty sure its A and B
Step-by-step explanation:
Slope is -6/5, so that leaves just A B and E
Plugged it in, only A and B were correct
Answer:
27.4 km
Step-by-step explanation:
vertical line- y
17 km/y= tan 54
y= 17/tan 54= 25.2 km
25.2/x= cos 23
x= 25.2/cos 23= 27.4 km
Alright, so in PEMDAS, we first do exponents. 3^2=9, and we then have 5(9)-3(3)+2. After that, we have multiplication, where we have 5*9 =45 and 3*3=9, resulting in 45-9+2 and eventually 38
