Answer:
It is the second triangle.
Step-by-step explanation:
This is because the area of the square is given as 25^2 as the perpendicular, 144^2 as the base, and the hypotenuse is 169^2.
Length of the perpendicular = 5^2 (Because 25^2 / 5^2)
Length of the base = 12^2
Length of the hypotenuse = 13^2
So, the Pythagoras theorem is,
=> 
=> 
This is true, because, 13*13 = 12*12 + 5*5
=> 169 = 144 + 25
=> 169 = 169
If my answer helped, kindly mark me as the brainliest!!
Thanks!!
Answer:
d is the answer
Step-by-step explanation:
perimeter of rect = 2(7+3) = 20
perimeter of square = 4 a =20
a = 5
Answer:
y - 2 = (1/8)(x + 8)
Step-by-step explanation:
The slope of the given line is -8. That means the slope of any line perpendicular to the given line will be the negative reciprocal of -8, which would be (1/8).
Then the desired equation is
y - 2 = (1/8)(x + 8)
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN
Note: Let us consider, we need to find the
and
.
Given:
In the given figure, BD is the angle bisector of ABC.
To find:
The
and
.
Solution:
BD is the angle bisector of ABC. So,




Divide both sides by 2.


Now,



And,





Therefore,
and
.