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o-na [289]
3 years ago
13

Trying to solve what is 3 1/3 x 6

Mathematics
2 answers:
nataly862011 [7]3 years ago
5 0
The answer is 18 1/3
ArbitrLikvidat [17]3 years ago
3 0
<span>3 1/3 x 6 4/5 10/3 x 34/5 then 10 x 34 = 340 then 3 x 5 = 15 340/15 (means 340 divided by 15 = 22.6 then because 5 is more than half you add one to the 22 and so your answer to the problem is 23</span>
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Help pls 2x^2+5x+3x+1
Oxana [17]

Answer: 2x^2+8x+1

Step-by-step explanation:

5x+3x=8x

4 0
2 years ago
I need help bad plz.
anyanavicka [17]

Answer:

2,57 * 10^5 or 257000

Step-by-step explanation:

(5,14 * 10^9) / (2 * 10^4) =

2,57 * 10^5 =

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6 0
3 years ago
Read 2 more answers
Can someone please help?​
TiliK225 [7]

Answer:

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7 0
3 years ago
Water is pumped into a tank at a rate of r (t)=30(1−e− 0.16t) gallons per minute, where t is the number of minutes since the pum
Vlad1618 [11]

Answer:

The total volume of the water in the tank after 20 minutes = 1220 gallons

Step-by-step explanation:

Rate of water pumped into the tank  r (t) = 30 (1 - e^{-0.16 t} )

Initial volume of water in the tank = 800 gallons

The water in the tank after 20 minutes = Initial volume of water in the tank + Volume of water being pumped in the tank

V_{total} = V_{i} + V_{pump}

V_{pump} = \int\limits^a_b {r(t)} \, dt

Where a = 0 , b = 20

Put the value of r (t) in above equation we get

V_{pump} = \int\limits^a_b {30 (1 - e^{-0.16t} )} \, dt

V_{pump} = 30 [ t + \frac{e^{-0.16t} }{0.16} ]

V_{pump} = 30[ (20- 0) + \frac{1}{0.16}(e^{-0.16 (20)}- e^{0}  )

V_{pump} = 420 gallon

Now, total volume in the tank

V_{total} = V_{i} + V_{pump}

V_{total} = 800 + 420

V_{total} = 1220 \ gallon

Therefore the total volume of the water in the tank after 20 minutes = 1220 gallons

3 0
3 years ago
PLS HELP ME WITH 5, 6, and 7 (SHOW WORK!!) + LOTS OF POINTS!
melisa1 [442]
Number 5 is c, number 6 is 'a'
7 0
3 years ago
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