Answer:
The probability of randomly selecting one employee who earned less than or equal to $45,000=0.00621
Step-by-step explanation:
We are given that
Mean,
Standard deviation,
We have to find the probability of randomly selecting one employee who earned less than or equal to $45,000.




Hence, the probability of randomly selecting one employee who earned less than or equal to $45,000=0.00621
Answer:
» For x-intercept, y is zero
<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>1</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>3</u><u>2</u><u> </u>

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>1</u><u>0</u><u>x</u><u> </u><u>+</u><u>2</u><u>4</u><u> </u><u>:</u>

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>6</u><u> </u><u>:</u>

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>2</u><u>5</u><u> </u><u>:</u>

<u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x²</u><u> </u><u>+</u><u> </u><u>8</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>2</u><u> </u><u>:</u>

Answer:
Irrational
Step-by-step explanation:
it can not be written as a simple fraction
Answer:
A=45m^2
Step-by-step explanation:
l*w