What is 0.4 as a fraction in lowest term
2 answers:
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The given expression is:
![\sqrt[5]{64 x^{7} w^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20)
The expression can be simplified as follows:
![\sqrt[5]{64 x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{6} x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{5}*2* x^{5}* x^{2} * w^{5} } \\ \\ = \sqrt[5]{ (2^{5} x^{5} w^{5} )*2 x^{2} } \\ \\ = \sqrt[5]{(2xw)^{5}*2 x^{2} } \\ \\ =2xw* \sqrt[5]{2x^{2} } ](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B6%7D%20%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B5%7D%2A2%2A%20x%5E%7B5%7D%2A%20x%5E%7B2%7D%20%2A%20w%5E%7B5%7D%20%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%20%282%5E%7B5%7D%20%20x%5E%7B5%7D%20%20w%5E%7B5%7D%20%29%2A2%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282xw%29%5E%7B5%7D%2A2%20x%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D2xw%2A%20%5Csqrt%5B5%5D%7B2x%5E%7B2%7D%20%7D%20%0A%20)
The expression can be simplified as follows:
<h3>Answer:</h3>
<em>Try the answers</em>
You can try the answers to see what works. You can expect all of the choices to match the first two terms, so try some farther down. Let's see if we can get -25 from -7.
a) 3*(-7) -4 = -21 -4 = -25 . . . . this one works
b) -7 -2 = -9 . . . . ≠ -25
c) -3(-7) +2 = 21 +2 = 23 . . . . ≠ -25
d) -2(-7) +1 = 14 +1 = 15 . . . . ≠ -25
The formula that works is the first one.
_____
<em>Derive it</em>
All these formulas depend on the previous term only, so we can write equations that show the required relationships. Let the unknown coefficients in our recursion formula be p and q, as in ...
Then, to get the second term from the first, we have
... 1·p +q = -1
And to get the third term from the second, we have
... -1·p +q = -7
Subtracting the second equation from the first gives ...
... 2p = 6
... p = 3 . . . . . . . this is sufficient to identify the first answer as correct
We can find q from the first equation.
... q = -1 -p = -1 -3 = -4
So, our recursion relation is ...
Answer:
29 is answer.
Step-by-step explanation:
Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.
To find average velocity of the object over the interval of time [1,3]
We know that derivative of s is velocity and antiderivative of velocity is position vector .
Since moving along a line equation of s is
use two point formula
gives the position at time t.
Average velocity in interval (1,3)
=