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3 years ago

What is 0.4 as a fraction in lowest term

Mathematics

2 answers:

Colt1911 [192]3 years ago

6 0

4/10 because it isnt a 1 so it will be less

miss Akunina [59]3 years ago

3 0

2/5 is the correct answer

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Ogether, teammates pedro and ricky got 2675 base hits last season. pedro had 283 more hits than ricky. how many hits did each pl

kondor19780726 [428]

Let Ricky = x; so equation: x + (x+283) = 2675 ; Re-arrange so x = Ricky = 1196 hits with Pedro 1196 + 283 = 1479.

7 0

3 years ago

The temperature today was 10 degrees colder than twice yesterday's temperature, t.

Aneli [31]

Answer: Today's temperature : 2t -10

Step-by-step explanation:

Hi, to write the expression of the statement given we have to analyze each phrase:

<em>Twice yesterday's temperature, t.</em> If t is yesterday’s temperature, twice that temperature equals 2t.

<em>The temperature today was 10 degrees colder than</em>: It means that we have to subtract 10 degrees :(-10)

Mathematically speaking:

Today's temperature : 2t -10

where t = yesterday's temperature

Feel free to ask for more if needed or if you did not understand something.

5 0

3 years ago

Gloria has red, green, and purple sweatshirts. she has black, white, and grey sweatpants. how many different outfits are possibl

OLga [1]

Nine outfits because you do 3 x 3

6 0

2 years ago

The following equation is a linear equation that has a slope of 3 and a y-intercept of positive 2:

Kryger [21]

The y intercept in the equation is -2. What is your question?

7 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

3 years ago