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3 years ago

The cross section of a right rectangular pyramid is a trapezoid if the pyramid is sliced how?

Mathematics

2 answers:

leonid [27]3 years ago

8 0

Triangle Rectangle Trapezoid Hexagon

Stells [14]3 years ago

6 0

It would be a trapezoid if you slice a triangle off of the corner.

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Write an expression in simplest form for the perimeter of each figure

Juli2301 [7.4K]

QUESTION 12

The given figure has five unequal sides.

The perimeter is the distance around the figure.

So we add all the lengths of the sides of the rectangle to get,

$Perimeter = 5x + 4x + 2.8y + 2x + 2.2y$

We regroup the like terms to obtain,

$Perimeter = 5x + 4x +2x + 2.8y + 2.2y$

This will simplify to give us,

$Perimeter = 11x + 5.0y$

$Perimeter = 11x + 5y$

QUESTION 13

The given figure has two pairs of sides that are equal in length and three unequal sides.

The perimeter can be found by adding all the lengths of the sides of the of the figure.

This will give us

$Perimeter = 6b + 5a + 3b + 4 + 3a + 2b + 5a$

We regroup like terms to obtain,

$Perimeter = 6b + 2b+ + 3b + 5a + 5a +3a + 4 +$

This finally simplifies to ,

.
$Perimeter = 11b + 13a + 4 +$

QUESTION 14

This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.

We add all the lengths of the sides of the plane figure to get,

$Perimeter =4j + 4j+ 4j+ 4j + 2h + 2h$

This will simplify to give us,

$Perimeter =16j + 4h$

6 0

3 years ago

5. Find the surface area of the cone. Round to<br> the nearest hundredth.<br> 2 ft<br> 6 ft

den301095 [7]

Answer:

$52.3m^2$

Step-by-step explanation:

Use these formulas

$A=\pi rl+\pi r^2\\l=\sqrt{r^2+h^2}$

Now solve

$A=\pi r(r+\sqrt{h^2+r^2} )\\=\pi *2*(2\sqrt{6^2+2^2} )\\=52.3m^2$

4 0

4 years ago

How many sixths are in 3 and 1 third ??

lorasvet [3.4K]

1 whole thing = 6 sixths
3 whole things = 18 sixths

1 third of a whole thing = 2 sixths of it

3 wholes plus 1 third = 18 sixths plus 2 sixths = 20 sixths

6 0

3 years ago

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bezimeni [28]

Quien sera, sera que de noche sale y de dia se va?

4 0

3 years ago

Read 2 more answers

For f(x) = 3x +1 and g(x) = x2 – 6, find (f- g)(x).

Fiesta28 [93]

Answer:

$\boxed{\sf (f-g)(x) = -{x}^{2} + 3x + 7}$

Given:

$\sf f(x) = 3x + 1 \\ \sf g(x) = {x}^{2} - 6$

To find:

$\sf (f - g)(x) = f(x) - g(x)$

Step-by-step explanation:

$\sf \implies(f - g)x = f(x) - g(x) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (3x + 1) - ( {x}^{2} - 6) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (3x + 1) + (- {x}^{2} + 6) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3x + 1 - {x}^{2} + 6 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - {x}^{2} + 3x + 1 + 6 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = -{x}^{2} + 3x + 7$

8 0

3 years ago