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3 years ago

Graph the inequality;y>-5x+3

1 answer:

7 0

Start your dot on 3 on the y axis. Move is downwards on the y axis by 5 everytime you move over once on the x axis. Shade all the stuff above the line since it says y is greater than -5x+3

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A rectangle has two different side lengths: One is (4p-5) inches. The other is (3p+2) inches. Find the perimeter of the rectangl

Anika [276]

The perimeter of rectangle is 14p-6.

Step-by-step explanation:

Given,

One side of rectangle = 4p-5 inches

Length of other side = 3p+2 inches

Perimeter of rectangle = 2( Length of one side + Length of other side)

$Perimeter = 2(4p-5+3p+2)\\Perimeter = 2(7p-3)\\Perimeter = 14p-6$

The perimeter of rectangle is 14p-6.

Keywords: rectangle, perimeter

Learn more about rectangle at:

#LearnwithBrainly

7 0

3 years ago

The solid below is dilated by a scale factor of 3. Find the volume of the solid created

Klio2033 [76]

The volume of the solid created upon dilation bythe scale factor of 3 is 5832 units³.

<h3>What is the volume of the dilated solid?</h3>

An image is dilated if the dimensions of the image is resized in a way that does not change the shape of the image. When an image is dilated, it is made larger.

Dimensions of the dilataed solid = 6 x 3 = 18

Volume = 18³ = 5832 units³

To learn more about dilation, please check: brainly.com/question/3457976

3 0

1 year ago

Lisa sold costume jewelry at a bazaar. The first hour she sold 2 bracelets and 3 rings for a total of $36.00 later a customer bo

saw5 [17]

2x + 3(6) = 36

2x + 18 = 36

2x = 18

x = 9

answer: each bracelet costs $9

7 0

2 years ago

The area in square feet of a rectangular field is x^2-100x+2400. The width, in feet is x-40. What is the length, in feet?

sattari [20]

Answer:

x-60

Step-by-step explanation:

You have to factor out the quadratic.

You know that one of the factors is x-40.

To factor:

Find a number that when added to -40, gives you -100, and also when multiplied, gives you 2400.

That such number is -60.

Add an x before it, and you get (x-60)

3 0

3 years ago

If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.

Sophie [7]

There's no if about it,

$f(x)=x^3+3x^2-x-3
$

has a zero $f(1)=0$ so $x-1$ is a factor. That's the special case of the Remainder Theorem; since $f(1)=0$ we'll get a remainder of zero when we divide $f(x)$ by $x-1.$

At this point we can just divide or we can try more little numbers in the function. It doesn't take too long to discover $f(-1)=0$ too, so $x+1$ is a factor too by the remainder theorem. I can find the third zero as well; but let's say that's out of range for most folks.

So far we have

$x^3+3x^2-x-3 = (x-1)(x+1)(x-r)$

where $r$ is the zero we haven't guessed yet. Again we could divide $f(x)$ by $(x-1)(x+1)=x^2-1$ but just looking at the constant term we must have

$-3 = -1 (1)(-r) = r$

so

$x^3+3x^2-x-3 = (x-1)(x+1)(x+3)$

We check $f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark$

We usually talk about the zeros of a function and the roots of an equation; here we have a function $f(x)$ whose zeros are

$x=1, x=-1, x=-3$

8 0

3 years ago

Read 2 more answers