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marusya05 [52]
2 years ago
5

Can someone help me with this lemonade table?

Mathematics
2 answers:
inessss [21]2 years ago
3 0

Answer:yes

times each number on the right by 2.5

Step-by-step explanation:

lisov135 [29]2 years ago
3 0

Answer:

2:5

12:30

40:100

100:250

7.5:18

5:12.5

.4:1

1:2.5

1/2:1.25

T:C

C:T

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Solve the proportion.
masya89 [10]

Answer:

14

Step-by-step explanation:

21 divided by 1.5 from the 3/2 you get 14

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3 years ago
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Pls help me its so hard
Vladimir79 [104]

X is 5

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3 years ago
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-7p (p+8)=21 is equal to
andrew11 [14]

We have the equation:

-7p(p+8)=21

So then we need to distribute -7p to the parentheses:

-7p^{2}+(-56p)=21

Then we need to set the equation equal to 0, so we must subtract 21 on both sides:

-7p^{2}-56p-21=0

Then we need to factor this. So we end up with:

7(-x^{2}-8p-3)=0

This is as much as this can be factored, so <u>we cannot go any further</u>.

3 0
3 years ago
Geometry need help. Will give brainlieest.
Elenna [48]

Answer:

x = 8

Step-by-step explanation:

The line segment inside the triangle is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides, that is

\frac{11x-4}{9x} = \frac{7x}{6x} ( cross- multiply )

6x(11x - 4) = 63x² ← distribute left side

66x² - 24x = 63x² ( subtract 63x² from both sides )

3x² - 24x = 0 ← factor out 3x from each term on the left side

3x(x - 8) = 0

Equate each factor to zero and solve for x

3x = 0 ⇒ x = 0

x - 8 = 0 ⇒ x = 8

But x > 0 , then x = 8

4 0
3 years ago
1. The standard deviation of sample size of n = 15 is 345 and the mean is 6784. Given that the
Aleksandr-060686 [28]

Answer:

The 90% confidence interval estimate of the mean of the population is between 6627 and 6941.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 15 - 1 = 14

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.761

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.761\frac{345}{\sqrt{15}} = 157

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 6784 - 157 = 6627

The upper end of the interval is the sample mean added to M. So it is 6784 + 157 = 6941

The 90% confidence interval estimate of the mean of the population is between 6627 and 6941.

7 0
3 years ago
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