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3 years ago

An oblique cylinder has a diameter of 14 units. The volume of the cylinder is 1,176π cubic units.

Mathematics

2 answers:

Effectus [21]3 years ago

4 0

Volume = πr^2h
1176π = π(14/2)^2x
1176 = 49x
x = 1176/49 = 24 units

wolverine [178]3 years ago

3 0

we know that

volume of the cylinder = $\pi *r^{2} *h$

in this problem

$diameter=14 units\\\\ r=\frac{14}{2} \\\\ r=7 units$

Volume= $1,176\pi$ units³

solve for h

$h=V/(\pi *r^{2} )\\ h=1,176\pi /(\pi *7^{2} )\\ h=24 units$

therefore

the answer is

the height of the cylinder is $24 units$

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3 years ago

Read 2 more answers

Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai

ollegr [7]

Answer:

The probability that the aircraft is overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is overloaded ?

Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

Now,

Probability that the aircraft is loaded be

P(X > 168 ) = P( $\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma}$ )

= P( z > $\frac{168 - 182.7}{39.6}$ )

= P( z > -0.371)

= 1 - P ( z ≤ -0.371 )

= 1 - P( z > 0.371)

= 1 - 0.00010363

= 0.9999

⇒P(X > 168) = 0.9999

As the probability of weight overload = 0.9999

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