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kolezko [41]
3 years ago
11

What is (12x - 32) in simplest form as an expression?

Mathematics
1 answer:
solmaris [256]3 years ago
5 0
The GCF of these two terms is 4.
Taking a 4 common:

4(3x - 8)

Hope this helps!
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4 0
3 years ago
Find an equation for the line that passes through the points (5.-5) and (-4,-2)
ANEK [815]

Answer:

\large\boxed{y=-\dfrac{1}{3}x-\dfrac{10}{3}\to x+3y=-10}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (5, -5) and (-4, -2).

Substiute:

m=\dfrac{-2-(-5)}{-4-5}=\dfrac{-2+5}{-9}=\dfrac{3}{-9}=-\dfrac{1}{3}

Put the value of the slope and the coordinates of the point (5, -5) to the equation of a line:

-5=-\dfrac{1}{3}(5)+b

-5=-\dfrac{5}{3}+b               <em>add 5/3 to both sides</em>

-\dfrac{15}{3}+\dfrac{5}{3}=b\\\\-\dfrac{10}{3}=b\to b=-\dfrac{10}{3}

Finally we have the equation of a line in the slope-intercept form:

y=-\dfrac{1}{3}x-\dfrac{10}{3}

Convert to the standard form <em>(Ax + By = C)</em>:

y=-\dfrac{1}{3}x-\dfrac{10}{3}          <em>multiply both sides by 3</em>

3y=-x-10              <em>add x to both sides</em>

x+3y=-10

4 0
3 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
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