A building casts a 50-foot shadow. Alex is 5 feet tall and casts a 6-foot shadow. Approximately how tall is the building?
2 answers:
Use ratios to solve this!
5:6 or 5/6 is the ration for Alex.
<span>Cross multiplication is used to solve this, so:
6x = 5(50) </span>
<span>6x = 250 </span>
<span>x = 250/6 </span>
<span>x = 41.67 which then rounds to 42 feet.
Also to your earlier question here is a screenshot of what the box should look like, and i have circled the attach file icon
</span>
5:6 or 5/6 is the ration for Alex.
<span>Cross multiplication is used to solve this, so:
6x = 5(50) </span>
<span>6x = 250 </span>
<span>x = 250/6 </span>
<span>x = 41.67 which then rounds to 42 feet.
Also to your earlier question here is a screenshot of what the box should look like, and i have circled the attach file icon
</span>
Answer:
Option B: 42 feet is the answer.
Step-by-step explanation:
The length of the shadow of the building is = 50 feet
Let the height of the building be = L
Height of Alex = 5 feet
Length of Alex's shadow = 6 feet
Now we will equate the ratios.
L = 41.67 ≈ 42 feet
So, the height of the building is approx 42 feet.
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Answer:
Number of restaurant-purchased meals eaten in a restaurant = 70
Number of restaurant-purchased meals eaten in a car = 22
Number of restaurant-purchased meals eaten in a home = 60
Step-by-step explanation:
Let the number of people that will eat in a restaurant be R.
Let the number of people that will eat in a car be C.
Let the number of people that will eat in a home be H.
From the information given in the problem we have,
R+C+H = 152 ____equation (1)
C+H-R = 12 ____equation (2)
R = H+10 ____equation (3)
1) Plugging in R=H+10 from equation 3 into the equation 2, we get
C+H-R=12
=> C+H-(H+10)=12
=> C+H-H-10=12
2) Cancelling out +H and -H, we get
C-10=12
3) Add 10 to both sides
C-10+10=12+10
4) Cancelling out -10 and +10, we get
C=22
5) Plugin C=22 in equation 1, we have
R+C+H = 152
=> R+22+H=152
Subtract 22 from both sides,
R+22+H-22=152-22
Cancelling out +22 and -22 from the left side, we get
R+H=130 ____let it be equation (4)
6) Plugin C=22 in equation 2, we have
C+H-R = 12
22+H-R = 12
Subtracting 22 from both the sides, we get
22+H-R-22 = 12-22
Cancelling out +22 and -22 from the left side,
H-R = -10 ____let it be equation (5)
7) Adding equation 4 and equation 5, we get
(R+H)+(H-R) = 130 + (-10)
=> R+H+H-R = 130-10
8) Cancelling out R and -R from the left side, we get
2H = 120
9) Dividing both sides by 2, we get
10) Cancelling out the 2's from the left side, we have
H=60
11) Plugging in C=22 and H=60 in the equation 1, we have
R+C+H = 152
=> R+22+60=152
=> R + 82 = 152
12) Subtracting 82 from both the sides, we get
R + 82 -82 = 152 -82
13) Cancelling out +82 and -82 from the left side, we get
R = 70
<em>So, C=22, H=60, R=70</em>