Please help me !!!!!!!!

Mathematics

1 answer:

frosja888 [35]3 years ago

4 0

What grade is this from?

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Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?

Sveta_85 [38]

$^{(1)}\ \ 4x^5-12x^4+6x=5x^3-2x\ \ ^{(2)}\\\\ \left\{\begin{array}{ccc}y=4x^5-12x^4+6x\ \ \ ^{(1)}\\y=5x^3-2x\ \ \ ^{(2)}\end{array}\right$

Answer: system nr 4.

7 0

3 years ago

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!

scZoUnD [109]

Answer:

"A" would be positive 2/ no, it is not because the opposite of 2 is -2

Step-by-step explanation:

negative and a negative is a positive

4 0

3 years ago

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Hello please answer need help

Levart [38]

2x + 2y = 42

2w + q = 35

2w + v = 29

x + q + y - v = ?

x = 7

y = 14

w = 3

q = 29

v = 23

7 + 29 + 14 - 23 =

The answer is 27

3 0

2 years ago

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What is 1 6/9 +5 9/7

lisabon 2012 [21]

$\longrightarrow{\green{7 \frac{20}{21}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$1 \frac{6}{9} + 5 \frac{9}{7} \\ \\ = \frac{15}{9} + \frac{44}{7} \\ \\ = \frac{15 \times 7}{9 \times 7} + \frac{44 \times 9}{7 \times 9} \\ \\ = \frac{105 + 396}{63} \\ \\ = \frac{501}{63} \\ \\ = \frac{167}{21} \\ \\ = 7 \frac{20}{21}$