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kondaur [170]
2 years ago
13

What is 1 6/9 +5 9/7

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
6 0

\longrightarrow{\green{7  \frac{20}{21}}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

1 \frac{6}{9}  + 5  \frac{9}{7}  \\   \\ =  \frac{15}{9}  +  \frac{44}{7}  \\  \\  =  \frac{15 \times 7}{9 \times 7}  +  \frac{44 \times 9}{7 \times 9}  \\  \\  =  \frac{105 + 396}{63}  \\  \\  =   \frac{501}{63}  \\  \\  =  \frac{167}{21}  \\  \\  = 7  \frac{20}{21}

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

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Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).
AveGali [126]

Answer:

<u>Question (a)</u>

Midpoint of a line segment:

M=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Given:

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\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)

<u>Question (b)</u>

Find slopes (gradients) of JL and MK then compare.  If the product of the slopes of JL and MK equal -1, then JL and MK are perpendicular.

\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}

Given:

  • J = (-2, 2)
  • L = (4, 0)

\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13

Given:

  • M = (3, 7)
  • K = (-1, -5)

\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3

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4 0
1 year ago
What is the simplification of <br> 5/√10
Sveta_85 [38]

5/ sqrt (10)

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5/ sqrt (10)*  sqrt(10)/sqrt(10)

5 * sqrt(10)

---------------

10

sqrt(10)

-----------

2

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Find the domain.

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(−∞,5)∪(5,∞)

Set-Builder Notation:

{x|x≠5}

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Natali5045456 [20]
The answer is 7/69.

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Since we want both of these events to occur together, we will multiply their probabilities:
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