Answer:
0.8041
Step-by-step explanation:
We know that
μ=72 and σ=5
and P(65<X<78)
We can determine the Z value as (X-μ)/σ
P( 65<X<78 )=P( 65-72< X-μ<78-72)
To fine the Z values:
From the standard normal tables:
to find P ( Z<-1.4)
From the standard normal tables:
Therefore
Answer:
0.1052
Step-by-step explanation:
Given that proportion of germination in the population is 94% =0.94
p = 0.96
Sample size = 220
Std dev of p = 
The probability that more than 96% of the 220 seeds in the packet will germinate
= 
Assumptions are np and nq >5 and also sample size >220 hence normal
The answer is c 143.ok bye
Answer:
0.35
Step-by-step explanation:
This probability distribution is shown below:
Pitch 1 2 3 4 5
Frequency 15 20 40 15 10
Probability 0.15 0.2 0.4 0.15 0.1
The probability that the pitcher will throw fewer than 3 pitches to a batter = P(X < 3)
X is the number of pitches thrown. Therefore:
P(X < 3) = P(X = 1) or P(X = 2)
The additive rule pf probability states that if two events X and Y are dependent events, the probability of X or Y occurring is the sum of their individual probability.
P(X < 3) = P(X = 1) or P(X = 2) = P(X = 1) + P(X = 2) = 0.15 + 0.2 = 0.35
The probability that the pitcher will throw fewer than 3 pitches to a batter = 0.35
