Answer: For the sum of 130
First: $90
Second: $40
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.
15a + 5 (130-a)=1550
15a+650-5a=1550
10a+650-650=1550-650
10a=900
a=$90 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
90+b=130
90-90+b=130-90
b= $40 was charged by the second mechanic
Answer:
range {3, 5, 6, 7 }
Step-by-step explanation:
to find the range substitute each value of x from the domain into f(x)
f(- 3) = -(- 3) + 4 = 3 + 4 = 7
f(- 2) = - (- 2 + 4 = 2 + 4 = 6
f(- 1) = - (- 1) + 4 = 1 + 4 = 5
f(1) = - 1 + 4 = 3
range y ∈ { 3, 5, 6, 7 }
Answer:D
Step-by-step explanation:
1
12
12
12
12
12=60
Answer:
44 rem
Step-by-step explanation:
Sorry i dont have an explanation
