What most likely occurred during this demonstration?
1 answer:
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17.40 sec is the time will take to smell second perfume after diffusion takes place
Acc. to Graham's law of Diffusion
Diffusion of Gas inversely proportional to square root of its Molecular mass.
<u>rb (Perfume B)</u>
ra(perfume A)
= its equation (1)
Give molar mass of Perfume A = 275 g/mol
molar mass of Perfume B= 205g/mol putting value in (1)
»
<em> its eq (2)</em>
» Perfume B will defuse 1:16 times faster than perfume A.
Hence, perfume B will be first smelled by Person.
Sf Equal volume V of two goes diffuse in t1 and t2 sec. respectively ton
Now,, from eq(2) toto
1/1:15 =
ta
Given tb =the smell of Perfume B as it diffuse faster
ta= 1.15 x 15 see
=ta2=17.40 sec
Learn more about diffuse here
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<u>Answer:</u> The volume of given mas of tin block at STP is
<u>Explanation:</u>
To calculate volume of of the substance, we use the equation:
We are given:
Mass of tin = 95.04 g
Density of tin =
Putting values in above equation, we get:
Hence, the volume of given mas of tin block at STP is