two perfumes A and B were released at the same time and you are standing 7.5metres away from both of them.molarmass of perfume A
1 answer:
17.40 sec is the time will take to smell second perfume after diffusion takes place
Acc. to Graham's law of Diffusion
Diffusion of Gas inversely proportional to square root of its Molecular mass.
<u>rb (Perfume B)</u>
ra(perfume A)
= its equation (1)
Give molar mass of Perfume A = 275 g/mol
molar mass of Perfume B= 205g/mol putting value in (1)
»
<em> its eq (2)</em>
» Perfume B will defuse 1:16 times faster than perfume A.
Hence, perfume B will be first smelled by Person.
Sf Equal volume V of two goes diffuse in t1 and t2 sec. respectively ton
Now,, from eq(2) toto
1/1:15 =
ta
Given tb =the smell of Perfume B as it diffuse faster
ta= 1.15 x 15 see
=ta2=17.40 sec
Learn more about diffuse here
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Answer:
monochlorinated products: 4
dichlorinated products: 12
Explanation:
Chlorination of alkanes is a reaction that takes place when the chlorine is in presence of light. This actually decomposes the chlorine, and one atom of Chlorine substracts an hydrogen from the alkane. Now, this hydrogen substracted comes usually from the most substitued carbon, because it's more stable (A tertiary carbon is more stable than a secondary carbon, and this more stable than primary).
When this happens, the other chlorine atom, goes as electrophyle in that carbon and formed the chlorinated product. Now, although a tertiary carbon is more stable, we can still have (in minor quantities) chlorinated products that comes from a secondary and primary carbon. The first picture shows the general mechanism of the chlorination, and the possible products for a monochlorinated.
The second picture shows the possible dichlorinated products, which are in higher quantities than the monochlorinated basicallu because of the variety of positions the chlorine can be. So, second picture shows all the products.
