Answer:
The concentration of the SO42- ion is 7.975 * 10 ^-4 M
Explanation:
<u>Step 1: </u>Data given
Volume of the 0.0250 M Ba(NO3)2 sample = 100 mL = 0.1 L
3.19 mL of Ba(NO3)2 solution is required to reach the end point of the titration
<u>Step 2</u>: The balanced equation
Ba(NO3)2 + SO42- → BaSO4 + 2NO3-
<u>Step 3:</u> Calculate number of moles Ba(NO3)2
The number of moles of Ba(NO3)2 = Molarity of Ba(NO3)2 * Volume
The number of moles of Ba(NO3)2 = 0.025M *3.19 x 10^-3 L
The number of moles of Ba(NO3)2 = 7.975 * 10 ^-5 moles
<u>Step 4:</u> Calculate number of moles SO42-
For 1 mole Ba'NO3)2 consumed, we need 1 mole of SO42-
For 7.975 * 10 ^-5 moles of Ba(NO3)2, we need 7.975 * 10 ^-5 moles of SO42-
<u>Step 5</u>: Calculate concentration of SO42-
[SO42-] = Moles SO42- / volume
[SO42-] = 7.975 * 10 ^-5 moles / 0.1L
[SO42-] = 7.975 * 10 ^-4 M
The concentration of the SO42- ion is 7.975 * 10 ^-4 M