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Helga [31]
3 years ago
15

1) Какое количество вещества Феррум (III) гидроксида вступает в реакцию с 15 г сульфатной кислоты?

Chemistry
1 answer:
EleoNora [17]3 years ago
3 0

i dont speak russian sorry

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Answer:

No

Explanation:

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Calculate the molality of a solution formed by adding 6.30 g NH4CL to 15.7 g of water
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Answer:

Molality = 7.5 mol/kg

Explanation:

Given data:

Mass of NH₄Cl = 6.30 g

Mass of water = 15.7 g (15.7/1000 =0.016 kg)

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Solution:

Formula of molality:

Molality = Moles of solute / mass of solvent in gram

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Number of moles = mass/ molar mass

Molar mass of  NH₄Cl = 53.491 g/mol

Number of moles = 6.30 g/  53.491 g/mol

Number of moles =  0.12 mol

Now we will calculate the molality.

Molality = Moles of solute / mass of solvent in gram

Molality =  0.12 mol / 0.016 kg

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zimovet [89]

Answer:

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Plz mark me brainliest if correct :)

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