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sweet [91]
3 years ago
6

PLsss help 15 points!

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
6 0

Answer:

90 square cm.

Step-by-step explanation:

For similar figures, the length of corresponding sides are proportional.

So we can write 4k = 6 where k is the proportionality constant.

<u>Note: </u>In terms of area, the scale factor would be k^2 and in terms of volume, it would be k^3y

Solving 4k = 6, we see that k = 6/4 or 3/2

We need area, so we <u><em>multiply area of ABC by k^2 to get area of PQR.</em></u>

<u><em>40(\frac{3}{2})^2\\=40(\frac{9}{4})\\=90</em></u>

<u><em /></u>

Area of PQR = 90 cm^2

S_A_V [24]3 years ago
5 0

Answer:

The area of △PQR is 90\ cm^{2}

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

so

Let

z-----> the scale factor

x---> the corresponding side triangle PQR

y---> the corresponding side triangle ABC

z=\frac{x}{y}

substitute the values

z=\frac{6}{4}=1.5

step 2

Find the area of triangle PQR

we know that

If two figures are similar, then the ratio of its areas  is equal to the scale factor squared

so

Let

z-----> the scale factor

x---> the area of triangle PQR

y---> the area of triangle ABC

z^{2} =\frac{x}{y}

we have

z=1.5

y=40\ cm^{2}

substitute the values

1.5^{2} =\frac{x}{40}

x=40(1.5^{2})=90\ cm^{2}

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sergij07 [2.7K]

Answer:

2x+12=24

first you subtract 12 from both sides

2x+12=24

-12. -12

The 12-12 should cancel itself, the rest of the equation you bring down to get

2x=12 (because 24-12=12)


Now you have 2x=12.
you then divide 2x by both sides.

2x=12

/2x=/2x

The 2x/2x cancels itself out so you then solve for 12/2x.

For this you just divide 12/2 which is 6!

x= 6 is your final answer.
to check this equation you can plug your number back into x to see if it is true! 2(6)+12=24.
6 times 2 is 12 and 12+12 is 24 so your answer (6) is true!


hope this helps! :D

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3 years ago
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In ΔOPQ, o = 58 cm, q = 13 cm and ∠Q=52°. Find all possible values of ∠O, to the nearest degree.
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Answer:

There is no possible triangles

Step-by-step explanation:

\frac{\sin A}{a}=\frac{\sin B}{b}

a

sinA

​  

=  

b

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​  

 

From the reference sheet (reciprocal version).

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​  

 

Plug in values.

\sin O=\frac{58\sin 52}{13}\approx 3.5157403

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​  

≈3.5157403O=\sin^{-1}(3.5157403)= \text{ERROR}

O=sin  

−1

(3.5157403)=ERROR

Sine cannot be greater than 1.

{No Possible Triangles}

No Possible Triangles

{}

{}

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36 : 90 in simplest form
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36:90 in simplest form would be 2:5

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