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sweet [91]
4 years ago
6

PLsss help 15 points!

Mathematics
2 answers:
Lubov Fominskaja [6]4 years ago
6 0

Answer:

90 square cm.

Step-by-step explanation:

For similar figures, the length of corresponding sides are proportional.

So we can write 4k = 6 where k is the proportionality constant.

<u>Note: </u>In terms of area, the scale factor would be k^2 and in terms of volume, it would be k^3y

Solving 4k = 6, we see that k = 6/4 or 3/2

We need area, so we <u><em>multiply area of ABC by k^2 to get area of PQR.</em></u>

<u><em>40(\frac{3}{2})^2\\=40(\frac{9}{4})\\=90</em></u>

<u><em /></u>

Area of PQR = 90 cm^2

S_A_V [24]4 years ago
5 0

Answer:

The area of △PQR is 90\ cm^{2}

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

so

Let

z-----> the scale factor

x---> the corresponding side triangle PQR

y---> the corresponding side triangle ABC

z=\frac{x}{y}

substitute the values

z=\frac{6}{4}=1.5

step 2

Find the area of triangle PQR

we know that

If two figures are similar, then the ratio of its areas  is equal to the scale factor squared

so

Let

z-----> the scale factor

x---> the area of triangle PQR

y---> the area of triangle ABC

z^{2} =\frac{x}{y}

we have

z=1.5

y=40\ cm^{2}

substitute the values

1.5^{2} =\frac{x}{40}

x=40(1.5^{2})=90\ cm^{2}

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Ian brought chocolate And vanilla cupcakes to school for his birthday 75 students decide to take a cupcake and 60% of them fit v
Brrunno [24]

Answer:

45 kids picked vanilla cupcake

Step-by-step explanation:

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6 0
3 years ago
Is there a known infinite product for e? What I mean is, it’s similar to an infinite series.
dedylja [7]

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6 0
3 years ago
The hypotenuse of a right angled triangle is 2√13 cm . If the smaller side is increased by 2 cm and the larger side is increased
White raven [17]

<em><u>Statement:</u></em>

The hypotenuse of a right angled triangle is 2√13 cm. If the smaller side is increased by 2 cm and the larger side is increased by 3 cm, the new hypotenuse will be √117 cm.

<em><u>To find out:</u></em>

The length of the larger side of the right angled triangle.

<em><u>Solution:</u></em>

Let us consider x as the smaller side and y as the larger side.

Then, in the right angled triangle,

x² + y² = (2√13)² ...(I) [By Pythagoras Theorem]

Now, if the smaller side is increased by 2 cm, then the smaller side will be (x + 2).

And if the larger side is increased by 3 cm, then the larger side will be (y + 3).

Then, in the new right angled triangle,

(x + 2)² + (y + 3)² = (√117)² [By Pythagoras Theorem]

or, x² + 2 × 2 × x + 2² + y² + 2 × 3 × y + 3² = (√117)²

or, x² + 4x + 4 + y² + 6y + 9 = (√117)²

or, x² + y² + 4x + 6y + 13 = (√117)²

Now, put the value of x² + y² from equation (I),

or, (2√13)² + 4x + 6y + 13 = (√117)²

or, (2 × 2 × √13 × √13) + 4x + 6y + 13 = (√117 × √117)

or, 52 + 4x + 6y + 13 = 117

or, 4x + 6y = 117 - 52 - 13

or, 4x + 6y = 52

or, 4x = 52 - 6y

or, x = \frac {(52 - 6y)}{4} ...(II)

Now, put the value of x of equation (II) in (I),

x² + y² = (2√13)²

or, \frac {(2704-624y +36y²)}{16} + y² = 52

or, \frac {(2704-624y +36y² + 16y²)}{16}= 52

or, 52y²-624y + 2704 = 52 × 16

or, 52y² - 624y + 2704 - 832 = 0

or, 52y² - 624y + 1872 = 0

or, 52(y² - 12y + 36) = 0

or, y²-12y +36 = 0 ÷ 52

or, y²-12y +36 = 0

or, (y)² - 2 × 6 × y + (6)² = 0

or, (y - 6)² = 0

or, y - 6=0

or, y = 6

We have taken y as the length of the larger side of the right angled triangle.

So, the length of the larger side is 6 cm.

<em><u>Answer:</u></em>

6 cm

Hope you could understand.

If you have any query, feel free to ask.

6 0
3 years ago
Can someone please do this for me please please i did the top but i dont get these so please
svlad2 [7]
I belive what you have to do is substitute the x with the numver given on the left, so the first one would be -3-13 which is -16, so then that means y= -16 , so the ordered pair would be (-3,-16)
Hope this helps!!
4 0
4 years ago
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