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faust18 [17]
3 years ago
10

Tell answer

Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer:

{ \tt{ {27}^{3} \times  {9}^{2}  \times 3 }} \\  = { \tt{ {3}^{3}  \times  {3}^{2} \times  {3}^{1}  }} \\  = { \tt{ {3}^{(3 + 2 + 1)} }} \\ { \tt{ =  {3}^{6} }}

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An airplane is sighted at the same time by two
tiny-mole [99]

I got 2.2

Step-by-step explanation:

I probably did the math wrong but i did my best and i hope this helped even a little!

4 0
2 years ago
Please help I’m really confused and need to learn this
egoroff_w [7]

Answer:

2.

Step-by-step explanation:

For #2, another way to word this question is: For which of the following trig functions is π/2 a solution? Well, go through them one by one. If you plug π/2 into sinθ, you get 1. This means that when x is π/2, y is 1. Try and visualize that. When y is 1, that means you moved off the x-axis; so y = sinθ is NOT one of those functions that cross the x-axis at θ = π/2. Go through the rest of them. For y = cos(π/2), you get 0. At θ = π/2, this function crosses the x-axis. For y = tanθ, your result is undefined, so that doesn't work. Keep going through them. You should see that y = secθ is undefined, y = cscθ returns 1, and y = cotθ returns 0. If you have a calculator that can handle trig functions, just plug π/2 into every one of them and check off the ones that give you zero. Graphically, if the y-value is 0, the function is touching/crossing the x-axis.

Think about what y = secθ really means. It's actually y = 1/(cosθ), right? So what makes a fraction undefined? A fraction is undefined when the denominator is 0 because in mathematics, you can't divide by zero. Calculators give you an error. So the real question here is, when is cosθ = 0? Again, you can use a calculator here, but a unit circle would be more helpful. cosθ = π/2, like we just saw in the previous problem, and it's zero again 180 degrees later at 3π/2. Now read the answer choices.

All multiples of pi? Well, our answer looked like π/2, so you can skip the first two choices and move to the last two. All multiples of π/2? Imagine there's a constant next to π, say Cπ/2 where C is any number. If we put an even number there, 2 will cut that number in half. Imagine C = 4. Then Cπ/2 = 2π. Our two answers were π/2 and 3π/2, so an even multiple won't work for us; we need the odd multiples only. In our answers, π/2 and 3π/2, C = 1 and C = 3. Those are both odd numbers, and that's how you know you only need the "odd multiples of π/2" for question 3.

6 0
3 years ago
Help please now help dont be childish will banned ​
belka [17]

Answer:

X, process, y

-2, 3(-2), -6

-1, 3(-1), -3

0, 3(0), 0

1, 3(1), 3

2, 3(2), 6

X = -2, -1, 0, 1, 2,

Y = -6, -3, 0, -3, -6

Step-by-step explanation:

Coordinates for the graph: (-2,-6), (-1,-3), (0,0), (1,3), (2,6)

Graph is the image I added onto this.

Solving for Y below:

3(-2)= -6

3(-1)= -3

3(0)= 0

3(1)= 3

3(2)= 6

Hope this helps.

5 0
2 years ago
Which is the simplified form of the expression ((2^-2)(3^4))^-3*((2^-3)(3^2))^2
Triss [41]

Answer:

2^36 3^48 is the correct answer

7 0
3 years ago
Use pascal's triangle to expand the binomial (x+3)^4
ratelena [41]

Answer: the answer is in the photo pls check this out and hope this helps can u give me brainliest

Step-by-step explanation:

6 0
3 years ago
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