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3 years ago

Someone help me a through f please.

Mathematics

1 answer:

slava [35]3 years ago

3 0

how many sides does each triangle
and cut them into equal parts

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A little help please

Dominik [7]

Answer: it’s 2, x = 2

Step-by-step explanation:

Hopes this helps !!!!

6 0

3 years ago

A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv

mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

$p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}$

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

$p=\frac{1}{6}$

Now, probability of failure is given by the formula:

$q=1-p=1-\frac{1}{6}=\frac{5}{6}$

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

$P(x) = ^nC_xp^xq^{n-x}$

Plug in all the given values and find the probability of 14 successes. This gives,

$P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087$

Therefore, the experimental probability of throwing a five is 0.087.

8 0

3 years ago

What is the value of X in the equation 4 3/10(2 2/5x+ 5 1/2)= 1/2( -3 3/5x + 1 1/5)?

Irina18 [472]

Answer: x= -1.02 or -95/93 or -1 2/93

Step-by-step explanation:

7 0

3 years ago

Rafael graphed a line that contains the points (4, –6) and (–2, 6). What is the slope of the line that he graphed?

KIM [24]

Answer:

-2

Step-by-step explanation:

Your welcome!

6 0

3 years ago

Read 2 more answers

What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal

jeka57 [31]

Slope of line = tan(120) = -tan(60) = - √3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-√3, or
B=A/√3.
Equation becomes
Ax+(A/√3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/√3)y+C)/sqrt(A^2+(A/√3)^2))
Substitute coordinates of origin (x,y)=(0,0) =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/√(4/3) => C=8*2/√3 = (16/3)√3

Therefore one solution is
x+(1/√3)+(16/3)√3=0
or equivalently
√3 x + y + 16 = 0

Check:
slope = -1/√3 .....ok
distance from origin
= (√3 * 0 + 0 + 16)/(sqrt(√3)^2+1^2)
=16/2
=8 ok.

Similarly C=-16 will satisfy the given conditions.

Answer The required equations are
√3 x + y = &pm; 16
in standard form.

You can conveniently convert to point-slope form if you wish.

4 0

3 years ago