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ExtremeBDS [4]
3 years ago
14

Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?

Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0

Answer:

There is no solution

Step-by-step explanation:

You can’t get a solution out of this

nata0808 [166]3 years ago
3 0

(A- No solution)

Ignore the folloqing;

(12345678901234567890)

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Find the value of x 7x+2=16<br>pls explain​
miskamm [114]

Answer:

2

Step-by-step explanation:

Given

7x + 2 = 16

Subtracting 2 from both sides

7x + 2 - 2 = 16 - 2

7x = 14

Dividing both sides by 7

7x / 7 = 14 /7

x = 2

Hope it will help :)

6 0
3 years ago
Read 2 more answers
Use the graph to state the solution for the system. (In other words, what is the solution for the system?)
timurjin [86]
(2,1) is the solution because its where they both intersect..
3 0
2 years ago
Brady used integer chips to model and solve a problem.
nata0808 [166]

Answer:

The answer is "3"

Step-by-step explanation:

In the question, some of the data is missing which is defined in the attached file. please find it.  

\to 7+(-4)\\\\\to 7-4\\\\\to 3

That's why 3 is correct.

6 0
2 years ago
(9, 18)and<br> (3, n) .<br> Find<br> n
Maru [420]

I don't seem to comprehend what you are asking?

8 0
3 years ago
A fair die is tossed 5 times. Let <img src="https://tex.z-dn.net/?f=%5Cdfrac%7Bm%7D%7Bn%7D" id="TexFormula1" title="\dfrac{m}{n}
Ray Of Light [21]

Answer:

m = 1

Step-by-step explanation:

We can suppose that the number we are looking for is for example 5.

(we can do so because the probability is the same for each number - it'sna fair dice)

For the first toss the probability we have 5 is 1/6 (we have 6 numbers on the dice and number 5 is just one of the possible 6 outcomes).

For the second toss the probability we have 5 is again 1/6.

For the rest of 3 tosses we don'tcare what number we will get( we have our two consecutive 5s), so all of the outcomes for the rest of 3 tosses are good for us (probability is 6/6 = 1)

Threfore, the probability to get two consecutive 5s is 1/6 * 1/6 * 1 * 1 * 1 = 1/36.

We can see that m = 1.

4 0
3 years ago
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