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Anna [14]
3 years ago
11

Choose the correct simplification of the quantity of x to the 7th power over y to the 9th power all raised to the 2nd power.

Mathematics
1 answer:
solniwko [45]3 years ago
6 0
X^7^2 = x^14 is the answer
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Please help I’m so close to passing math
kirill115 [55]

Answer:

$0.14 per ounce of salsa

Step-by-step explanation:

2.80/20

Move decimal to make the number a whole number

(Have to move the decimal the same amount of spaces)

28/200

0.14

Hope this helps. Have a nice day

8 0
2 years ago
Read 2 more answers
If an object travels 400 m in 253 s what is its speed in m/s?
Doss [256]
Speed = distance / time 

<span>Speed = 400 / 253 </span>

<span>Speed = 1.58 m/s approx</span>
6 0
3 years ago
Read 2 more answers
Whats the radical of 12?
Harrizon [31]

Answer:

2√3

Step-by-step explanation:

So √12 is in radical form. I think what you are asking for is to reduce the expression to its **simplest** readical form.

So 12 = 4*3, √12 = √4 * √3.

So 12 = 4*3, √12 = √4 * √3.

We can ‘reduce’ this by noting that √4 =2, so the expression becomes 2√3.

This cannot be further reduced because 3 isn’t a square or divisible by a square, so 2√3 is the simplest radical form.

4 0
3 years ago
Find the length , in centimeters , if the width is 48 <br><br> 1. 10 centimeters
ruslelena [56]
It is 40 becuase points and due
6 0
3 years ago
A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the followi
Stels [109]

Answer:

One of the balls is yellow: 0.36

At least one ball is red:0.73

Both balls are green:0.3

Both balls are of the same color:0.266

Step-by-step explanation:

To get the probability equally likely of choosing balls we use the following formula

P=# of possibilities that meet the condition / #of equally likely possibilities.

#of equally likely possibilities of the first experiment is 1+2+3=6

#of equally likely possibilities of the second experiment is 1+2+3 -1 =5 ( no replacement)

We choose 2 balls so we have to multiple  or add the probability of the 2 experiments,  that depends on the case

One of the balls is yellow:

1 experiment P{ One of the balls is yellow }= 1/6

2 experiment P{ One of the balls is yellow }= 1/5

P{ One of the balls is yellow }= 1/6+1/5=11/30

At least one ball is red:

1 experiment P{ One of the balls is red }= 2/6

2 experiment P{ One of the balls is red }= 2/5

P{ One of the balls is yellow }= 2/6+2/5=22/30

Both balls are green:

1 experiment P{ Both balls are green }= 3/6

2 experiment P{ Both balls are green }= 3/5

P{ Both balls are green }= 3/6*3/5=0.3

Both balls are of the same color

1 experiment P{ Both balls are green }= 3/6

2 experiment P{ Both balls are green }= 2/5

P{ Both balls are green }= 3/6*2/5=0.2

1 experiment P{ Both balls are red }= 2/6

2 experiment P{ Both balls are red }= 1/5

P{ Both balls are red }= 3/6*3/5=0.066

Both could happens so we add the probabilities

P{ Both balls are of the same color }=0.2+0.066=0.266

8 0
3 years ago
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