A survey indicated that 3 out of 5 doctors use brand X aspirin. If 2000 doctors were surveyed, how many used brand X?

These lines are perpendicular. Is this statement true or false?

umka2103 [35]

False they are not exact recipricals

5 0

2 years ago

Select the correct answer from each drop-down menu. The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 =

nignag [31]

The general form of the equation of a circle is,

x² + y² + Dx + Ey + F = 0, where D, E, F are constants.

The given equation is 7x² + 7y² − 28x + 42y − 35 = 0. So, to convert this equation into a general form we just need to get rid of the leading coefficient 7.

Hence, divide both sides of the equation by 7. So,

$\frac{7x^2+ 7y^2-28x + 42y-35}{7} =0$

x² + y² − 4x + 6y − 5=0.

So, the general form of the equation is x² + y² − 4x + 6y − 5=0.

7 0

2 years ago

Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region

yanalaym [24]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

Concepts:

Area of Square = s²

s = side

Area of Triangle = bh/2

b = base
h = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

Question # 16

Step One: Find the total area of two squares

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

Step Two: Find the area of the blank triangle

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

Step Three: Subtract the area of the blank triangle from the total area

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

Step One: Find the length of PT

Given:

PR = 4 cm
RT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

Step Two: Find the length of S to PT perpendicularly

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Three: Find the area of ΔPST

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Four: Find the length of Q to PT perpendicularly

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Five: Find the area of ΔPQT

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Six: Combine area of two triangles to find the total area

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

6 0

2 years ago

Which of the following equations has the same solutions as the equations 3x+2y=-12

Marianna [84]

B, C, E, F

<h2>Explanation:</h2>

In this problem, we have the following equation of a line written in Standard form:

$3x+2y=-12$

So we need to choose the equations that has the same solutions as this equation. If we multiply each equation by a constant term and find the same solution as the given equation, then they will have the same solution. This is only true fro options B, C, E and F.

Option B.

$-3x-2y= 12 \\ \\ Multiply \ both \ sides \ by \ -1: \\ \\ (-1)(-3x-2y)=(-1)(12) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option D.

$15x+10y= -60 \\ \\ Multiply \ both \ sides \ by \ 1/5: \\ \\ (\frac{1}{5})(15x+10y)=(\frac{1}{5})(-60) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option E.

$6x+2y= -12 \\ \\ Multiply \ both \ sides \ by \ 1/2: \\ \\ (\frac{1}{2})(6x+2y)=(\frac{1}{2})(-24) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option F.

$1.5x+y= -6 \\ \\ Multiply \ both \ sides \ by \ 2: \\ \\ (2)(1.5x+y)=(2)(-6) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

For the other options, there is no any constant term that multiplies both sides of the equation and gives us the same given equation.

<h2>Learn more:</h2>

About this subject: brainly.com/question/8810210

#LearnWithBrainly

7 0

2 years ago

Julian spends 85 min on HW each day. If 20% of the time is spent on math HW, how many minutes a day is Julian spending on math H

allsm [11]

The answer is 17 minutes

7 0

2 years ago

Read 2 more answers