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Natasha2012 [34]

4 years ago

11

Jon has 3/5 of a dollar, pasha has $0.65, Marie has 7/10 of a dollar, and Karen has $0.62.who has the smallest the smallest amou

nt

1 answer:

Zigmanuir [339]4 years ago

8 0

Answer:

Jon

Step-by-step explanation:

Jon: 3/5 (divide)

=0.6

Pasha: 0.65

Marie: 7/10 (divide)

=0.7

Karen: 0.62

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10. Elaine is buying cube shaped blocks to add to her mantle as decoration. 1 point

podryga [215]

Answer:

my brain says (c) or (b) so, my answer would be (C)

Step-by-step explanation:

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4 years ago

. What is the slope of the following line: x=-4 *<br>a.0<br>b. undefined <br>c.-4<br>d.1

s344n2d4d5 [400]

Answer:

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5 0

3 years ago

May I please get help with other this problem for I am confused as I have tried multiple times to get the right answer

Aleks [24]

Using pythagoras

$\begin{gathered} x^2=16^2+12^2 \\ x^2=256+144 \\ x^2=400 \\ \text{Take the square root} \\ x=20 \end{gathered}$

The final answer

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1 year ago

What is the following product

Genrish500 [490]

For this case we must find the product of the following expression:

$\sqrt [3] {5} * \sqrt {2}$

By definition of properties of powers and roots we have:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

We rewrite the expression using the lowest common index of 6, then:

$5 ^ {\frac {1} {3}} * 2 ^ {\frac {1} {2}} =$

We rewrite the terms in an equivalent way:

$5 ^ {\frac {2} {6}} * 2 ^ {\frac {3} {6}} =$

We rewrite the expression using the property mentioned:

$\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =$

We combine using the product rule for radicals:

$\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}$

So:

$\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}$

ANswer:

Option b

4 0

3 years ago

The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2000 there were about

olchik [2.2K]

Answer:

Number of fish in 2006 = 845 fishes (Approx.)

Step-by-step explanation:

Given;

Number of fish in 2000 = 1,150 fishes

Decreasing rate = 5% per year

Find:

Number of fish in 2006

Computation:

Exponential decay function:

F = P[1-r]ⁿ

Number of year = 2006 - 2000

Number of year = 6 year

Number of fish in 2006 = 1,150[1-5%]⁶

Number of fish in 2006 = 1,150[1-0.05]⁶

Number of fish in 2006 = 1,150[0.95]⁶

Number of fish in 2006 = 1,150[0.735]

Number of fish in 2006 = 845.25

Number of fish in 2006 = 845 fishes (Approx.)

4 0

3 years ago