Putting a = 6 and b= 3/2 in eqn. (1) the required equation is:-
x /6 + 2.y/3 = 1. or, x + 4y = 6. Answer.
Domain = {x|x = 2, 9, 6}
Range = {y|y = c, 0}
I think this is the answer? I tried, it's better to fill it in than to leave it blank :/
Answer:
6
come to z o o m
z o o m id 85675494491 pwd eu3nFG
Answer:
y = 
Step-by-step explanation:
m = 
<span>To solve these GCF and LCM problems, factor the numbers you're working with into primes:
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5
</span><span>We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
</span><span>Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have.
So, B = 2*3*3*3*7 = 378.</span>
