3 years ago

HELP PLZ 50 POINTS!!!!!!

Mathematics

2 answers:

Bess [88]3 years ago

6 0

Answer:Long time ago so thanks for the points

Step-by-step explanation:

lianna [129]3 years ago

4 0

Answer:

Hi :)

Step-by-step explanation:

i think i will actually do this, im just saving my spot

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The solutions to the equation f(x) = g(x) are -2 and 1. If f and g are graphed on the same coordinate plane, which statement mus

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Write as a product: 25a2−0.01b10

Yakvenalex [24]

Answer:

We conclude that:

$25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$

Step-by-step explanation:

Given the expression

$25a^2-0.01b^{10}$

Rewrite $25a^2-0.01b^{10}$ as $\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2$

$25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2$

Apply difference of two squares formulas:

$x^2-y^2=\left(x+y\right)\left(x-y\right)$

$\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)$

$=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$ ∵ $\sqrt{0.01}=0.1$ ,

Therefore, we conclude that:

$25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$

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