Answer:
The period when its more than halfway
= 2 < t ≤ 2.83 seconds ( to nearest hundredth).
Step-by-step explanation:
When is is halfway down the ramp d = 3920/2 = 1960 cm, so:
1960 = 490 t^2
t^2 = 1960/490 = 4
t = 2 seconds.
When it reaches the bottom d = 3920 :
t^2 = 3920/490 = 8
t = 2.83 seconds.
The answer is c cuz the shaded overlapping section represents the answer
Answer:
63
Step-by-step explanation:
hhehehehhehehehehh hope this helps
1. The fourth graph: D
2. The first graph: A
<span>data: 2, 5, 9, 11, 17, 19
</span>
median is the middle number
median = (9+11)/2 = 10
mean = average
mean = (2 + 5 + 9 + 11+ 17 + 19)/6
mean = 63/6
mean = 10.5
