Question

Just need help on this one problem about a triangle

Answer 1

Given:

ΔABC is an equilateral triangle.

AB = 7.5x, BC = 6x + 3 and CA = 10x - 5

To find:

The value of x.

Solution:

In equilateral triangle, all sides are equal.

AB = BC = CA

$7.5x=6x + 3 = 10x - 5$

Take any two sides only:

AB = BC

$7.5 x=6 x+3$

Subtract 6x from both sides.

$7.5 x-6 x=6x+3-6x$

$1.5 x=3$

Divide by 1.5 on both sides.

$\frac{1.5 x}{1.5}=\frac{3}{1.5}$

$x=2$

The value of x is 2.