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DiKsa [7]
3 years ago
14

Question 2 (5 points) What's the explicit rule for the sequence 9, 14, 19, 24, ...?

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

adding by 5

Step-by-step explanation:

,...............................

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Please help with this too!
expeople1 [14]

Answer:

b>1

Step-by-step explanation:

3(3b-4)> 8b-11\\9b-12> 8b-11\\9b-8b> -11+12\\b> -11+12\\b>1

3 0
3 years ago
Can someone please explain? I don't understand
Nezavi [6.7K]
A solution for a pair of lines means that they are equal to each other. This occurs when they instersect. Since the lines have the same slope, but are not the same line, they are parallel, so they will never intersect. This means there are zero solutions.
Hope this helps!
6 0
3 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0
3 years ago
What's the cube root of 2744000
Paraphin [41]
The cube root of 2744000 is 140
4 0
4 years ago
Graph the line with slope 1/5 and y-intercept-2
Arturiano [62]
You want to start at -2 on the y line wich is the vertical line then 1/5 is rise over run so you rise (go up) one and run ( go right)5
8 0
2 years ago
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