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2 years ago

Would it be A. B. C. D.

Mathematics

2 answers:

gtnhenbr [62]2 years ago

7 0

Answer:

A. is the answer

BlackZzzverrR [31]2 years ago

6 0

The answer is a as it is a no

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If the graph of f(x) = x^2, how will the graph be affected if it is changed to f(x) = 3r^2?

Eva8 [605]

Answer:

the graph curve will goes above f(x)=x^2.f(x)=3*x^2 curve will also give higher value same value of x .

Step-by-step explanation:

3 0

3 years ago

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A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li

svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem

15 drivers are randomly selected, so $n = 15$ .

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year. This means that $\pi = 0.08$ .

What is the probability of getting 3 or more who were involved in a car accident last year?

This is $P(X \geq 3)$ .

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

$P(X < 3) + P(X \geq 3) = 1$

$P(X \geq 3) = 1 - P(X < 3)$

In which

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{15,0}.(0.08)^{0}.(0.92)^{15} = 0.2863$

$P(X = 1) = C_{15,1}.(0.08)^{1}.(0.92)^{14} = 0.3734$

$P(X = 2) = C_{15,2}.(0.08)^{2}.(0.92)^{13} = 0.2273$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2863 + 0.3734 + 0.2273 = 0.887$

Finally

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.887 = 0.113$

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

5 0

3 years ago

ASAP PLEASE!!!!!!!!!

dezoksy [38]

B. 1 to 90 I’m pretty sure

8 0

3 years ago

24 POINTS!!!!!!!!!!!!!!!

inessss [21]

Scale factors are multipiled
a times scale factor turns into b

so
0.5 times scale factor=0.8
divide both sides by 0.5
scale factor=1.6
the scale factor is 1.6

4 0

3 years ago

A work crew has 3/4 tons of stone to divide evenly among four sidewalks how much stone does the crew use for each sidewalk

spin [16.1K]

3/16 this is the answer

5 0

3 years ago

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