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andrew11 [14]
3 years ago
5

The world's most powerful tugboats are built in Finland. One of these boats can do 9.8 × 107 J of work through a distance of 35

m. What is the force exerted by the tugboat? 
Mathematics
1 answer:
kkurt [141]3 years ago
3 0
<span>2.8 x 10^6 N We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that: F * 35m = 9.8 x 10^7 kg*m^2/s^2 Solving for F, gives F * 35m = 9.8 x 10^7 kg*m^2/s^2 F = 9.8 x 10^7 kg*m^2/s^2 / 35m F = 2.8 x 10^6 kg*m/s^2 F = 2.8 x 10^6 N So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
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yulyashka [42]

Answer : The specific heat of the metal is, 2178.67J/kg^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of ice = 2000J/kg^oC

m_1 = mass of metal = 1.00 kg

m_2 = mass of ice = 1.00 kg

T_f = final temperature of mixture = -8.88^oC

T_1 = initial temperature of metal = 5.00^oC

T_2 = initial temperature of ice = -24.0^oC

Now put all the given values in the above formula, we get:

(1.00kg)\times c_1\times (-8.88-5.00)^oC=-[(1.00kg)\times 2000J/kg^oC\times (-8.88-(-24.0))^oC]

c_1=2178.67J/kg^oC

Therefore, the specific heat of the metal is, 2178.67J/kg^oC

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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