Answer:
Lets say we have (-1)^(1.5)
Step-by-step explanation:
(-1)^(1.5) = (-1)^(3/2)
= (√(-1))^3 which has no solution in the real number field, as √(-1) does not exist.
In the complex number field √(-1) = i, and (-1)^(1.5) = i^3 = -i.
Answer: It's C. The third one.
Step-by-step explanation:
HOPE THIS HELPS!!!! : )
Answer:
b
Step-by-step explanation:
Answer:
60
Step-by-step explanation:
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The numerical value of the mean voltage is 25.47 V
To find the numerical value of the mean voltage, V of V(t) = 40 sin(t), we integrate V(t) with respect to t over the interval [0.π]
So,
![V = \frac{1}{\pi } \int\limits^\pi _0 {V(t)} \, dt \\V = \frac{1}{\pi } \int\limits^\pi _0 {40sint} \, dt \\V = \frac{1}{\pi } [-40cost]_{0}{\pi } \\V = \frac{1}{\pi } -[40cos\pi - 40cos0]\\\\V = \frac{1}{\pi } (-[40 X (-1) - 40 X 1})\\V = -\frac{1}{\pi } [-40 - 40]\\V = \frac{80}{\pi } \\V = 25.465 V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5Cint%5Climits%5E%5Cpi%20_0%20%7BV%28t%29%7D%20%5C%2C%20dt%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5Cint%5Climits%5E%5Cpi%20_0%20%7B40sint%7D%20%5C%2C%20dt%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5B-40cost%5D_%7B0%7D%7B%5Cpi%20%7D%20%20%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20-%5B40cos%5Cpi%20%20-%2040cos0%5D%5C%5C%5C%5CV%20%3D%20%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%28-%5B40%20X%20%28-1%29%20-%2040%20X%201%7D%29%5C%5CV%20%3D%20-%5Cfrac%7B1%7D%7B%5Cpi%20%7D%20%5B-40%20-%2040%5D%5C%5CV%20%3D%20%5Cfrac%7B80%7D%7B%5Cpi%20%7D%20%5C%5CV%20%3D%2025.465%20V)
V ≅ 25.47 V
So, the numerical value of the mean voltage is 25.47 V
Learn more about mean volatage here:
brainly.com/question/17928028