Exercice 1
1 answer:
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F = 1.8C + 32
С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒ (-10, 14)
С = 0 ⇒ F = 1.8·(0) + 32 = 32 ⇒ (0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒ (10, 50)
С = 20 ⇒ F = 1.8·(20) + 32 = 68 ⇒ (20, 68)
С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒ (-10, 14)
С = 0 ⇒ F = 1.8·(0) + 32 = 32 ⇒ (0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒ (10, 50)
С = 20 ⇒ F = 1.8·(20) + 32 = 68 ⇒ (20, 68)
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
