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3 years ago

Need help from the same last question. (I dont need to do #10)

Mathematics

1 answer:

AysviL [449]3 years ago

8 0

8. The y-intercept is -10. You can find this by just seeing where the line would hit the y-axis. This is basically the starting point so the Scuba Diver's decent started at -10m.

9. You have the y-intercept so put that in slope-intercept form. y=mx+b

y=mx - 10

Now find the slope by picking two points and using the slope formula. I'll use
(30,-6) and (50,-4), and then plug in the values. 30 = x1, -6 = x2, 50 = x2, -4 = -4. Simplify.

m= y2-y1 -4 - (-6) 2 1
-------- = ----------- = --- / 2 = ---
x2-x1 50 - 30 20 10

You might be interested in

A smoke jumper jumps from a plane that is 1700 ft above the ground. The function y = -16t2 + 1700 gives the jumper's height y in

lakkis [162]

Answer: (A) 6.6 sec (B) 6.89 sec

Step-by-step explanation:

y = -16t² + 1700

1000 = -16t² + 1700

-1700 -1700

-700 = -16t²

÷-16 ÷-16

43.75 = t²

√43.75 = √t²

6.6 = t

***********************************

y = -16t² + 1700

940 = -16t² + 1700

-1700 -1700

-760 = -16t²

÷-16 ÷-16

47.5 = t²

√47.5 = √t²

6.89 = t

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%7B%5Cbold%20%5Cred%7B%20%5Csum%20%5Climits_%7B8%7D%5E%7B4%7D%20%7Bx%7D%5E%7B2%7D%2

kiruha [24]

Answer:

No solution

Step-by-step explanation:

We have

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

For the sum it is not correct to assume

$\sum_{x=8}^{4}x^2= 8^2 + 7^2+6^2+5^2+4^2 = 64+49+36+25+16 = 190$

Note that for

$\sum_{x=a}^b f(x)$

it is assumed $a\leq x \leq b$ and in your case $\nexists x\in\mathbb{Z}: a\leq x\leq b$ for $a>b$

In fact, considering a set $S$ we have

$\sum_{x=a}^b (S \cup \varnothing) = \sum_{x=a}^b S + \sum_{x=a}^b \varnothing$ that satisfy $S = S \cup \varnothing$

This means that, by definition $\sum_{x=a}^b \varnothing = 0$

Therefore,

$\sum_{x=8}^{4}x^2 = 0$

because the sum is empty.

For

$9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

we have other problems. Actually, this case is really bad.

Note that $\cos^2(\infty)$ has no value. In fact, if we consider for the case

$\lim_{x \to \infty} \cos^2(x)$ , the cosine function oscillates between $[-1, 1]$ , and therefore it is undefined. Thus, we cannot evaluate

$9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

and then

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

has no solution

7 0

3 years ago

Brian drives 215 miles at an average speed. He then travels 75 more miles at a speed

Sedaia [141]

His average speed for the first trip is 43 mph

Since Brian's average speed is x and he travels the first part for 215 miles in time t.

So, his distance d = xt

Also, the travels 75 more miles at a speed of 15 mph.

Since distance = speed time, the time he takes to cover this distance is

t' = distance/speed = 75 mi/15 mph = 5 hours

Since he covers both distances in the same time, we have that t = t' = 5 hours.

So, his average speed for the first trip x = d/t

= 215 mi/5 h

= 43 mph

His average speed for the first trip is 43 mph

Learn more about average speed here:

brainly.com/question/13605708

6 0

3 years ago

A rectangular cardboard sheet has a length that is 1.5 times greater than the width. Is it possible to make a topless box with a

Andreyy89

Answer:

Yes, it is possible to make a topless box with a volume of 6080 cm3 out of this cardboard sheet.

The dimensions of the cardboard sheet are 54 cm x 36 cm

Step-by-step explanation:

Let

x ----> the length of the cardboard sheet

y ----> the width of the cardboard sheet

we know that

$x=1.5y$ ----> equation A

The volume of the topless box is

$V=LWH$

where

$V=6,080\ cm^3$

$L=x-2(8)=(x-16)\ cm$

$W=y-2(8)=(y-16)\ cm$

$H=8\ cm$

substitute

$6,080=(x-16)(y-16)8$ ----> equation B

substitute equation A in equation B

$6,080=(1.5y-16)(y-16)8$

$6,080/8=(1.5y-16)(y-16)$

$760=1.5y^2-24y-16y+256$

$760=1.5y^2-40y+256$

$1.5y^2-40y+256-760=0$

$1.5y^2-40y-504=0$

Solve for y

Solve the quadratic equation by graphing

The solution is y=36 cm

see the attached figure

Find the value of x

$x=1.5y$ ----> $x=1.5(36)=54\ cm$

therefore

Yes, it is possible to make a topless box with a volume of 6080 cm3 out of this cardboard sheet.

The dimensions of the cardboard sheet are 54 cm x 36 cm

7 0

3 years ago

Read 2 more answers

What is 33 in expanded form

ZanzabumX [31]

33 expanded form = 30+3

7 0

3 years ago

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