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wariber [46]
3 years ago
15

You're wrapping up a gift that is 10 inches by 5 inches by 4 inches in dimension. You are paying $0.02/square inch. How much wil

l the wrapping paper cost you?
Mathematics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

£4

Step-by-step explanation:

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Helpppppppppppppppppppppppppp
Ymorist [56]

She has to add 2 more quarters for 108 more days.

8 0
3 years ago
Chau's shop sells quarts of ice cream each day. How much is this in pints?
barxatty [35]

Answer:

One quart is 2 pints

Step-by-step explanation:

multiply the number of quarts by 2 to get the number of pints.

5 0
3 years ago
Savannah is planning to buy enough raffle
Alborosie

Answer:

20 tickets

Step-by-step explanation:

tickets/total tickets * 100% = 10% chance to win the raffle

x/200*100=10

solve for x

x/200 =  10/100

x = 200(0.1)

x = 20

6 0
3 years ago
The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar
Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, H_0 : \mu \leq  3.5%

    ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, H_0 : \mu \leq  3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

                T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where,  \bar X = sample mean debt ratio of Ohio banks = 6%

             s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 1.83%

             n = sample of banks = 7

So, test statistics = \frac{6-3.5}{\frac{1.83}{\sqrt{7} } }  ~ t_6

                             = 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

7 0
3 years ago
290 pennies are equal to how many dimes
ExtremeBDS [4]
29 dimes
............
6 0
3 years ago
Read 2 more answers
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