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Nataly_w [17]
2 years ago
10

Which equation are equivalent to 1/5+2/3|2-x|=4/15?

Mathematics
2 answers:
notsponge [240]2 years ago
6 0

Answer:

The answer is A and C

Step-by-step explanation:

I just did the work

Good luck

disa [49]2 years ago
5 0

Answer:

• 2/3|2 -x| = 1/15

• |2 -x| = 1/10

• 1/5 +|4/3 -2/3x| = 4/15

Step-by-step explanation:

Starting with the given equation, subtract 1/5 = 3/15.

(2/3)|2 -x| = 4/15 - 3/15

(2/3)|2 -x| = 1/15 . . . . . . . . matches the first choice

Now, multiply by 3/2.

|2 -x| = 3/30

|2 -x| = 1/10 . . . . . . . . . . . . matches the third choice

___

If you decide to distribute the coefficient 2/3 instead, you have

1/5 + |2·2/3 -x·2/3| = 4/15

1/5 + |4/3 -2/3x| = 4/15 . . . . matches the selected choice

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Which is an equation in point slope form of the line that passes through the points 7,5 and -4,-1
Free_Kalibri [48]

Answer:

the second option is the correct one

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

To calculate m use the slope formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (7, 5) and (x₂, y₂ ) = (- 4, - 1)

m = \frac{-1-5}{-4-7} = \frac{-6}{-11} = \frac{6}{11}

Use either of the 2 points as (a, b)

using (- 4, - 1), then

y- (- 1) = \frac{6}{11}(x - (- 4)), that is

y + 1 = \frac{6}{11}(x + 4)

6 0
2 years ago
PLEASE PLEASE HELP! Find the measure of APB^.
Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

\angle CAT=\angle CBT=90^{\circ}

Since angle BAT is equal to 65°, angle CAB has measure

\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

\angle CBA=\angle CAB=25^{\circ}

The sum of the measures of all interior angles in triangle is always 180°, so

\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}

8 0
3 years ago
(1,4,9,4,10,8,42)
mixas84 [53]
The answer is has to be D
7 0
2 years ago
Solve each system of equations below by the substitution method. And show your work.
Simora [160]
Instead of typing it all on here, I included my explanations with the work.

7 0
2 years ago
I am not sure if i did this right she wants us to distribute and get only one x on one side and find the answer.
umka21 [38]


I got x=18


3(x-4)-2(3x+4)=4(3-x)+5x+4

3x-12-6x-8=12-4x+5x+4

3x-20=16+x

2x=36x

x=18

5 0
2 years ago
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