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Firlakuza [10]
3 years ago
7

DFGI is a trapezoid with midsegment EH. What is DI?

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

a. 8 cm

Step-by-step explanation:

Given:

EH = 6 cm

FG = 4.00 cm

Based on the mid-segment theorem of a trapezoid, we have:

EH = ½(FG + DI)

Plug in the values

6 = ½(4 + DI)

Multiply both sides by 2

6*2 = 4 + DI

12 = 4 + DI

12 - 4 = 4 + DI - 4

8 = DI

DI = 8 cm

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Answer:

Hello! answer: 65

Step-by-step explanation:

60 × 60 = 3600

25 × 25 = 625

3600 + 625 = 4225

√4225 = 65

65 × 65 = 4225 therefore c = 65 Hope that helps!

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What is 5 3/4 minus 4 1/10?
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5 3/4 -4 1/10
= 23/4 -41/10
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What is the value of X X+11 2x+8 3x+1
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Please please help
777dan777 [17]

Step-by-step explanation:

Statement. Reason

→ 9(x-6)+41 = 75. Transposing the like terms.

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Use a graphing utility to graph the function and visually estimate the limits.
levacccp [35]

The value of the \lim_{x \to 0} f(x) and \lim_{x \to \frac{\pi }{3} } f(x) are 0 and 1.153 .

<h3></h3><h3>What is the limiting value of a function?</h3>

Limiting Value of a Function. The function's limit is the value of the function as its independent variable, such as x approaches a certain value called the limiting value. For simple equations, this is similar to finding out the value of y when x has a unique value.

Given that,

f(x) = 4x cos x

First to calculate the limit value of the given function at x=0.

\lim_{x \to 0} f(x) = \lim_{x \to 0} 4x cosx

                   = 4×0×1                              (∵ cos0 = 1)

\lim_{x \to 0} f(x) = 0

Similarly,

\lim_{x \to \frac{\pi }{3} } f(x) = \lim_{x \to \frac{\pi }{3} } 4x cosx

                     =  4×\frac{\pi }{3}×cos\frac{\pi }{3}

                     =  4×\frac{\pi }{3}×\frac{1}{2}                          (∵cos60° = \frac{1}{2})

\lim_{x \to \frac{\pi }{3} } f(x)  = 1.153

Hence, The value of the \lim_{x \to 0} f(x) and \lim_{x \to \frac{\pi }{3} } f(x) are 0 and 1.153.

To learn more about the limit of the function from the given link:

brainly.com/question/23935467

#SPJ9

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1 year ago
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