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Mashcka [7]
4 years ago
10

Consider the three functions below. f(x) = Negative StartFraction 6 Over 11 EndFraction (eleven-halves) Superscript x g(x) = Sta

rtFraction 6 Over 11 EndFraction (eleven-halves) Superscript negative x h(x) = Negative StartFraction 6 Over 11 EndFraction (eleven-halves) Superscript negative x Which statement is true?
Mathematics
2 answers:
Setler79 [48]4 years ago
9 0

Answer:

The correct option is;

The ranges of f(x) and h(x) are similar and different from the ranges of g(x)

Step-by-step explanation:

Here we have the functions given as follows;

f(x) = -6/11 (11/2)ˣ

g(x) = 6/11 (11/2)⁻ˣ

h(x) = -6/11 (11/2)⁻ˣ

from the above equations, it can be seen that f(x) and h(x) are always negative while g(x) is always positive

f(x) and h(x) are symmetric about the y axis while g(x) and h(x) are symmetric about the x axis

Also h(x) is the inverse of f(x) hence the ranges of f(x) and g(x) are similar and are different from the ranges of g(x).

IrinaVladis [17]4 years ago
3 0

The answer is <u><em>c</em></u> on edg :)

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Step-by-step explanation:

OK, let's assume it this way:

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Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!<em>=</em><em>(</em><em>2</em><em>.</em><em>1</em><em>!</em><em>-</em><em>1</em><em>!</em><em>)</em><em>+</em><em>(</em><em>3</em><em>.</em><em>2</em><em>!</em><em>-</em><em>2</em><em>!</em><em>)</em><em>+</em><em>(</em><em>4</em><em>.</em><em>3</em><em>!</em><em>-</em><em>3</em><em>!</em><em>)</em><em>+</em><em>.</em><em>.</em><em>.</em><em>+</em><em>(</em><em>(</em><em>n-1</em><em>)</em><em>n</em><em>!</em><em>-</em><em>n</em><em>!</em><em>)</em><em>=</em><em>(</em><em>2</em><em>!</em><em>-</em><em>1</em><em>!</em><em>)</em><em>+</em><em>(</em><em>3</em><em>!</em><em>-</em><em>2</em><em>!</em><em>)</em><em>+</em><em>(</em><em>4</em><em>!</em><em>-</em><em>3</em><em>!</em><em>)</em><em>+</em>

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