Here are the first three terms of a different sequence.

Need help ASAP <br> questions in the pics i have sent

Cloud [144]

Answer:

Step-by-step explanation:

Picture 1

In right triangle ABC,

Side AB is the opposite side of angle C.

Picture 2

In triangle MKL,

tan(∠M) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

= $\frac{KL}{KM}$

= $\frac{15}{8}$

Option (1) is the answer.

Picture 3

In ΔXYZ,

sin(∠Z) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

= $\frac{XY}{XZ}$

For the length of XY we will apply Pythagoras theorem in ΔXYZ,

XZ² = XY² + YZ²

XY² = XZ² - YZ²

= (40)² - (32)²

XY = √576

= 24

sin(Z) = $\frac{24}{40}$

sin(Z) = $\frac{3}{5}$

Picture 4

In right triangle DEF,

Cos(D) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

= $\frac{EF}{DF}$

= $\frac{75}{72}$

= $\frac{25}{24}$

Picture 5

In ΔABC,

tan(63°) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

tan(63°) = $\frac{BC}{AB}$

AB = $\frac{BC}{\text{tan}(63)}$

AB = $\frac{8}{\text{tan}(63)}$

AB = 4.0762 ≈ 4 m

Option (3) will be the answer.

7 0

2 years ago

Write an equation in slope-intercept form and then in standard form for each line described. y-intercept -2; x-intercept 5

Xelga [282]

Hello
the line passes by A ( 0 ; -2) and B (5 ; 0) equation : y = ax+b
a is a slop : a = (yb - ya)/(xb -xa)
a = (0+2)/(5-0)
a =2/5
y = (2/5)x+b
if x=5 and y= 0
0 = (2/5)(5)+b
b= - 2
the equation is : y = (2/5)x-2

5 0

2 years ago

Write 6,730,000 in scientific notation

Sergio [31]

6.7x10^6 always the the decimal points go between the first 2 numbers, and you count the numbers of decimal places following it to get your scientific exponent

8 0

2 years ago

Half of the sum of nine and p is the same as p minus three

Nataly_w [17]

Answer:

3÷(9+p)=p-3

Step-by-step explanation:

use the distributive property

7 0

2 years ago

Estimate a 15% tip on a dinner bill of $61.53 by first rounding the bill amount to the nearest $10

adelina 88 [10]

well, 61.53 is really 10 + 10 + 10 + 10 + 10 + 10 + 1.53.

well, 1.53 doesn't really come nowhere near close to round up to 10, so it boils down to 0, so 61.53 will just be 10 + 10 + 10 + 10 + 10 + 10 + 0 or just 60 once rounded up, now, what's 15% of 60?

$\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{15\% of 60}}{\left( \cfrac{15}{100} \right)60}\implies 9$

well, we can get the 15% of 61.53 by just (15/100) * 61.53

however, the exercise is asking on rounding it up to "tens" first

61.53 has "10" six times plus 1.53, the rounding happens with the "surplus"

in this case the surplus is 1.53.

now, for rounding anything the tipover point is at the half, for $10 the half is $5, so if the amount is $5 or more, rounds up to $10, if less than that goes to 0.

1.53 is nowhere near 5, which is the halfpoint or tipover point, because of that, it rounds up to 0, so 61.53 rounded up to "tens" only will be "six tens" only, or 60.

5 0

4 months ago